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编写高级sql查询

[英]writing advanced sql query

I am working with this schema: http://classes.engr.oregonstate.edu/eecs/winter2013/cs275-400/tester/bsgSchema.html 我正在使用以下架构: http : //classes.engr.oregonstate.edu/eecs/winter2013/cs275-400/tester/bsgSchema.html

and I am trying to achieve: Find the fname, lname and ship_instance id of all people who do not have Viper certificaton but are assigned to at least one instance of a Viper class ship (this includes all variants of Viper class ships). 我正在尝试实现:查找所有没有获得Viper认证但至少被分配给一个Viper级飞船实例(包括Viper级飞船的所有变体)的人的fname,lname和ship_instance id。 Return a row for every ship/person combination.) 为每个船舶/人员组合返回一行。)

I am close. 我近了 I have written the following query: 我写了以下查询:

SELECT DISTINCT p.fname, p.lname, si.id from bsg_people p
INNER JOIN bsg_ship_assignment sa ON sa.pid = p.id
INNER JOIN bsg_ship_class sc ON sc.id = sa.cid
INNER Join bsg_ship_instance si ON si.class = sa.cid
WHERE p.id NOT
IN (
    SELECT cp.pid
    FROM bsg_cert_people cp
    INNER JOIN bsg_cert c ON c.id = cp.cid
    WHERE cp.cid = '2'
)
AND sc.name = 'viper' 

My query returns a number of extra instances. 我的查询返回了许多额外的实例。

SELECT p.fname
     , p.lname
     , sk.id
  FROM bsg_people p 
  LEFT 
  JOIN bsg_cert_people cp  
    ON cp.pid = p.id 
  LEFT 
  JOIN bsg_cert c 
    ON c.id = cp.cid 
   AND c.title = 'viper'
  JOIN bsg_ship_assignment ps
    ON ps.pid = p.id
  JOIN bsg_ship_instance sk
    ON sk.id = ps.sid
   AND sk.class = ps.cid
  JOIN bsg_ship_class k
    ON k.id = sk.class
 WHERE k.name = 'viper'
   AND c.id IS NULL;
+---------+----------+------+
| fname   | lname    | id   |
+---------+----------+------+
| William | Adama    | 8757 |
| Lee     | Adama    |  121 |
| Lee     | Adama    |  289 |
| Lee     | Adama    | 1104 |
| Laura   | Roslin   | 2343 |
| Gaius   | Baltar   |  289 |
| Samuel  | Anders   | 3203 |
| Samuel  | Anders   | 8757 |
| Brendan | Costanza | 7242 |
| Brendan | Costanza | 2343 |
+---------+----------+------+

SELECT bsg_people.fname, bsg_people.lname, bsg_ship_instance.id FROM bsg_people 从bsg_people中选择bsg_people.fname,bsg_people.lname,bsg_ship_instance.id

INNER JOIN bsg_ship_assignment ON bsg_ship_assignment.pid = bsg_people.id 内联接bsg_ship_assignment ON bsg_ship_assignment.pid = bsg_people.id

INNER JOIN bsg_ship_instance ON bsg_ship_assignment.sid = bsg_ship_instance.id 内连接bsg_ship_instance ON bsg_ship_assignment.sid = bsg_ship_instance.id

INNER JOIN bsg_ship_class ON bsg_ship_class.id = bsg_ship_instance.class 内连接bsg_ship_class ON bsg_ship_class.id = bsg_ship_instance.class

WHERE bsg_people.id NOT IN bsg_people.id不在的位置

(

SELECT bsg_cert_people.pid FROM bsg_cert_people 从bsg_cert_people选择bsg_cert_people.pid

INNER JOIN bsg_cert ON bsg_cert_people.cid = bsg_cert.id 内联bsg_cert ON bsg_cert_people.cid = bsg_cert.id

WHERE bsg_cert.title = 'Viper' WHERE bsg_cert.title ='毒蛇'

)

AND bsg_ship_class.name = 'viper' AND bsg_ship_class.name ='毒蛇'

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