uint8缓冲区的c ++数组

Question

In C++, I have an uint8 buffer of the length [len]. When allocating a single buffer I do this:

uint8 *buffer= new uint8[len];

What's the syntax for allocating an array of such buffers? This gives me a syntax error:

uint8** buffers = new uint8[len]*[bufferCount];

Answer 1

The way you initialize a 2d array is as follows:

uint8** buffers = new uint8*[bufferCount];
for (int i = 0; i < bufferCount; i++)
    buffers[i] = new uint8[len];

Answer 2

#include <vector>

using byte_vector = std::vector<uint8_t>;
using byte_vector_vector = std::vector<byte_vector>;


// example of a 1-dimension vector
auto v1 = byte_vector(len, inital_value);

// example of a [2, len] vector
auto v_of_v = byte_vector_vector { 
  byte_vector(len, initial_value),
  byte_vector(len, initial_value)
};

// print the uint8 at (0,1)
std::cout << v_ov_v[0][1] << std::endl;

Answer 3

You asked

What's the syntax for allocating an array of such buffers?

You can use:

uint8** buffers = new uint8*[bufferCount];

However, use this only if std::vector is absolutely not an option for some reason.