awk语句以一行输出
[英]awk statement to get output in one line
问题描述
Please suggest - 
请建议-
Input File - 输入文件 -
G238740
G316342
G748951
G952443
G955221
G952842
G767727
G339717
G712953
Command i tried: 我尝试的命令：
awk -F";" '{ print "displayName == \""$1"\" " "||" }' input
Current output - 电流输出-
displayName == "G238740" ||
displayName == "G316342" ||
displayName == "G748951" ||
displayName == "G952443" ||
displayName == "G955221" ||
displayName == "G952842" ||
displayName == "G767727" ||
displayName == "G339717" ||
displayName == "G712953" ||
Desired output , How to get output in one single line 所需的输出，如何在一行中获得输出
displayName == "G238740" || displayName == "G316342" || displayName == "G748951"
1 个解决方案
解决方案1
2 已采纳 2015-03-31 06:31:54
Use printf instead of print , so it won't add a newline. 使用printf代替print ，所以它不会添加换行符。 And then conditionally print the || 然后有条件地打印|| separator on all lines but the first: 除第一行外的所有行上的分隔符：
awk '{printf("%sdisplayName == \"%s\"", (NR == 1 ? "" : " || "), $1)}
END {print ""}' input
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