如何在PHP中使用Google搜索查询？

Question

I am trying to use Google Search query in my website, I need to get website URLs for the text I sent to the query, the code works fine for limited results, but then it stops working after some time, maybe Google disables it for some time?

Here is the code:

        $cleanQuery = str_replace(" ","+",$text);
        $url = 'http://www.google.com/search?q='.$cleanQuery;
        $scrape = file_get_contents($url);

$text is the text entered by the user while searching. But the problem is it works only for sometime, then it stops.

Working example: http://www.alleffort.com/tools/findurl.php

If you enter some text in the textarea, then on submits it should retrieve all the related information, but it is not working.

Answer 1

The problem is probably the string you are appending to the url:

 $cleanQuery = str_replace(" ","+",$text);

This does not prepare the string correctly for use in a query string, you would need to encode more characters than just the space.

Instead, you should use urlencode() :

$cleanQuery = urlencode($text);

Answer 2

This code most probably help you for solving problem

 <?php $xmlDoc=new DOMDocument(); $xmlDoc->load("links.xml"); $x=$xmlDoc->getElementsByTagName('link'); //get the q parameter from URL $q=$_GET["q"]; //lookup all links from the xml file if length of q>0 if (strlen($q)>0) { $hint=""; for($i=0; $i<($x->length); $i++) { $y=$x->item($i)->getElementsByTagName('title'); $z=$x->item($i)->getElementsByTagName('url'); if ($y->item(0)->nodeType==1) { //find a link matching the search text if (stristr($y->item(0)->childNodes->item(0)->nodeValue,$q)) { if ($hint=="") { $hint="<a href='" . $z->item(0)->childNodes->item(0)->nodeValue . "' target='_blank'>" . $y->item(0)->childNodes->item(0)->nodeValue . "</a>"; } else { $hint=$hint . "<br /><a href='" . $z->item(0)->childNodes->item(0)->nodeValue . "' target='_blank'>" . $y->item(0)->childNodes->item(0)->nodeValue . "</a>"; } } } } } // Set output to "no suggestion" if no hint was found // or to the correct values if ($hint=="") { $response="no suggestion"; } else { $response=$hint; } //output the response echo $response; ?>