Android okhttp GET 请求中添加查询参数

Question

Is there a way to add query params ( ?param1=val1&param2=val2 ) to a GET request using okhttp in Android?

I am looking for an API and not manually adding the params in a loop and escaping the values.

Answer 1

Try HttpUrl class (in okhttp package).

---

//adds the pre-encoded query parameter to this URL's query string
addEncodedQueryParameter(String encodedName, String encodedValue)

//encodes the query parameter using UTF-8 and adds it to this URL's query string
addQueryParameter(String name, String value)

Note: if there are already name/value pairs with this name, these functions will just add another pair

---

setEncodedQueryParameter(String encodedName, String encodedValue)

setQueryParameter(String name, String value)

Note: if there are already name/value pairs with this name, these functions will remove them and only after that add this new pair

---

Example:

HttpUrl url = new HttpUrl.Builder()
    .scheme("https")
    .host("www.google.com")
    .addPathSegment("search")
    .addQueryParameter("q", "polar bears")
    .build();

Answer 2

Use HttpUrl .

Say you already have a String url ready, just want to append the queries:

HttpUrl url = HttpUrl.parse("http://www.google.com/search").newBuilder()
   .addQueryParameter("q", "cat videos")
   .build();

For the details about query parameters, see Vitaly's answer, or refer to the documentation .

Answer 3

This is not possible with the current version of okhttp, there is no method provided that will handle this for you .

However, Jesse Wilson , one of okhttp's developers, has stated that

We're adding a new HttpUrl class that can do this in the next release.

Answer 4

import android.net.Uri
var url = Uri.parse(urlWithoutQueryParams).buildUpon().appendQueryParameter("key","value").build().toString()

Answer 5

Example:

HttpUrl url = new HttpUrl.Builder()
    .scheme("https")
    .host("www.google.com")
    .addPathSegment("search")
    .addQueryParameter("q", "polar bears")
    .build();
System.out.println(url);

output:

https://www.google.com/search?q=polar%20bears

• Reference: Okhttp HttpUrl

Answer 6

val url = "https://api.flutterwave.com/v3/transfers/fee".toHttpUrlOrNull()?.newBuilder()
            ?.addQueryParameter("amount", "100")
            ?.addQueryParameter("currency", curr)
            ?.build()

 val request = url?.let {
        okhttp3.Request.Builder()
            .header("Authorization", "Bearer ${HeaderBearerKey}")
            .header("Content-Type", "application/json")
            .url(it)
            .build()
    }