将cURL命令转换为PHP

Question

I have the following cURL command:

curl -i -H "Accept: application/json" -H "Content-Type: application/json; charset=utf-8" -H "TC: 000000" -H "ST: 000000" -X POST -d '[{"Param1" : "Value1", "Param2" : "Value2"} ]' http://www.somesaasprovider.com/

It works fine when I'm running it in the terminal and I get the expected output.

However, when I try to use the same command but adapted to PHP, I get no result.

The PHP version looks like this:

error_reporting(E_ALL);
ini_set('display_errors', '1');

$ch = curl_init('http://www.somesaasprovider.com');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'POST');
curl_setopt($ch, CURLOPT_POSTFIELDS, '[{"Param1" : "Value1", "Param2" : "Value2"}]');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'Accept: application/json',
    'Content-Type: application/json; charset=utf-8',        
    'TC' => '000000',
    'ST' => '000000')
);

$response = curl_exec($ch);
$response = json_decode($response);

print_r($response);

What am I doing wrong?

Thanks.