[英]is there a better way to write the query that I wrote
I have the following query which gives me the overall status of a project. 我有以下查询,它给了我一个项目的总体状态。 I was wondering if there was a better way to write the same query. 我想知道是否有更好的方法来编写相同的查询。
an example schema for the table: 表的示例模式:
CREATE TABLE `test_status`
(
`test_id` int
(11) NOT NULL,
`group_id` int
(11) NOT NULL,
`sub_test_id` int
(11) NOT NULL,
`project_id` int
(11) NOT NULL,
`collection_status` varchar
(20) DEFAULT NULL,
`labeling_status` varchar
(20) DEFAULT NULL,
`upload_status` varchar
(20) DEFAULT NULL,
`upload_date` date DEFAULT NULL,
`disk_number` int
(11) DEFAULT NULL,
`subject_id` varchar
(10) DEFAULT NULL,
`collection_id` varchar
(25) DEFAULT NULL,
`assigned_to` int
(11) DEFAULT NULL,
`assigned_on` date DEFAULT NULL,
`turned_in_date` date DEFAULT NULL,
PRIMARY KEY
(`test_id`,`group_id`,`sub_test_id`,`project_id`));
My Query: 我的查询:
select
(select count(*)
from test_status
where project_id = 7 and collection_status = 'COLLECTED') as collected,
(select count(*)
from test_status
where project_id = 7 and collection_status = 'SCHEDULED') as scheduled,
(select count(*)
from test_status
where project_id = 7 and collection_status = 'CORRUPTED') as corrupted,
(select count(*)
from test_status
where project_id = 7 and collection_status is NULL) as 'not collected',
(select count(*)
from test_status
where project_id = 7 and ((labeling_status = 'GOOD' and (upload_status != 'UPLOADED' or upload_status != 'QUEUED')) or (labeling_status = 'Labeled'))) as 'Labeled',
(select count(*)
from test_status
where project_id = 7 and (labeling_status = 'RAW') or (labeling_status = 'ASSIGNED') ) as 'to be labeled',
(select count(*)
from test_status
where project_id = 7 and labeling_status = 'RE-LABEL') as 'Re-label',
(select count(*)
from test_status
where project_id = 7 and (upload_status = 'UPLOADED' or upload_status = 'QUEUED')) as 'Uploaded',
(select count(*)
from test_status
where project_id = 7 and labeling_status = 'GOOD' and upload_status is null) as 'ready to be uploaded';
You can try to use condition aggregate function will be better. 你可以尝试使用条件聚合函数会更好。
let the condition in CASE WHEN
让在条件CASE WHEN
SELECT
COUNT(CASE WHEN collection_status = 'COLLECTED' THEN 1 END),
COUNT(CASE WHEN collection_status = 'SCHEDULED' THEN 1 END),
COUNT(CASE WHEN collection_status = 'CORRUPTED' THEN 1 END),
COUNT(CASE WHEN collection_status is NULL THEN 1 END),
COUNT(CASE WHEN ((labeling_status = 'GOOD' and (upload_status != 'UPLOADED' or upload_status != 'QUEUED')) or (labeling_status = 'Labeled'))THEN 1 END),
COUNT(CASE WHEN (labeling_status = 'RAW') or (labeling_status = 'ASSIGNED') THEN 1 END),
COUNT(CASE WHEN labeling_status = 'RE-LABEL' THEN 1 END),
COUNT(CASE WHEN (upload_status = 'UPLOADED' or upload_status = 'QUEUED') THEN 1 END),
COUNT(CASE WHEN labeling_status = 'GOOD' and upload_status is null THEN 1 END)
FROM test_status
WHERE project_id = 7
Or you can try a simpler way, SUM
with bool
(0 or 1) to count
或者您可以尝试更简单的方法,使用bool
(0或1) count
SUM
SELECT
SUM(collection_status = 'COLLECTED'),
SUM(collection_status = 'SCHEDULED'),
SUM(collection_status = 'CORRUPTED' ),
SUM(collection_status is NULL ),
SUM(((labeling_status = 'GOOD' and (upload_status != 'UPLOADED' or upload_status != 'QUEUED')) or (labeling_status = 'Labeled'))),
SUM((labeling_status = 'RAW') or (labeling_status = 'ASSIGNED') ),
SUM(labeling_status = 'RE-LABEL' ),
SUM((upload_status = 'UPLOADED' or upload_status = 'QUEUED')),
SUM(labeling_status = 'GOOD' and upload_status is null )
FROM test_status
WHERE project_id = 7
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