将** kwargs传递给带有args的函数。 最佳做法？

Question

Suppose I have a function that takes a lot of positional arguments like:

def foo(a, b, c, d, e):
  ...

It can be nice to call it by passing in a deconstructed dictionary like this:

args = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
foo(**args)

Is there anything to watch out for when calling an argument like this?

The first thing that comes to mind is that it will break if the functions argument names change, but that doesn't seem worse then accepting **kwargs in the function and accessing them with kwargs['a'] , kwargs['b'] , ect.

Is there anything else I'm missing?