在SQL Server中将数据透视表行按组列

Question

I am looking for a code which can transpose row to column using the group by in the SQL Server 2008.

This is my table :

Name   |  Stdy   |  Val
-------+---------+-------
Kunjan | Technic |  80
Kunjan | Sains   |  90
Kunjan | Sport   |  60
Shone  | Technic |  60
Shone  | Sains   |  80
Shone  | Sport   |  70
Peudd  | Technic |  85
Peudd  | Sains   |  75
Peudd  | Sport   |  90

What I want to eventually display is something like this (for the data above):

Stdy    | Kunjan | Shone | Peudd
--------+--------+-------+-------
Technic |  80    |  60   |  85
Sains   |  90    |  80   |  75
Sport   |  60    |  70   |  90

Any help would be appreciated.

Thanks in advance.

Answer 1

this can be done using PIVOT operator

select  *
from    yourtable
        pivot 
        (
            max(Val)
            for Name in ([Kunjan], [Shone], [Peudd])
        ) p

or conditional CASE statement. There are lots of example, just do a search on it

EDIT : for dynamic case

declare @sql    nvarchar(max),
        @col    nvarchar(max)

select  @col    = isnull(@col + ',', '') + Name
from    yourtable
group by Name

print   @col 

select  @sql    = 
'
select  *
from    youtable
        pivot 
        (
            max(Val)
            for Name in (' + @col + ')
        ) p
'

print   @sql
exec    sp_executesql @sql