如何在没有IFNULL的情况下获得相同的结果-MySQL

Question

I made sqlfiddle example: http://sqlfiddle.com/#!9/3bbb6d/1/0

    SELECT
        `Image`.`id`,
        `Topic`.`title`
    FROM
        `images` AS `Image`, `topics` AS `Topic`
    WHERE
        `Image`.`vender_id` = 'model' AND `Topic`.`id` = IFNULL((SELECT article_id FROM articles_images WHERE image_id = `Image`.`id` ORDER BY id DESC LIMIT 0, 1), 999)
    ORDER BY
        `Image`.`id` DESC
    LIMIT 10

Result: (CORRECT)

id  title
8   
7   
5   CCC
4   DDD
3   BBB
2   BBB
1   

Without IFNULL(..., 999) http://sqlfiddle.com/#!9/3bbb6d/2

Result:

id  title
5   CCC
4   DDD
3   BBB
2   BBB

But I also need records with empty " title " => id: 8, 7 and 1

Is there a way to have all records without using IFNULL ?

+++ UPDATED +++

@Used_By_Already

Thank you for your help. I got result: (It has two records with ID:5)

id  title
8   (null)
7   (null)
5   AAA              << X
5   CCC              << correct 
4   DDD
3   BBB
2   BBB
1   (null)

There are two records with the same ID : 5, how can I get only one of them that is highest by articles_images.id ?

Result that I need to get is:

id  title
8   
7   
5   CCC
4   DDD
3   BBB
2   BBB
1   

Answer 1

Use left joins:

SELECT
     I.id
    ,T.title
FROM images AS i
LEFT JOIN articles_images AS ai ON I.id = ai.image_id
LEFT JOIN topics AS t on ai.article_id = t.id
WHERE i.vender_id = 'model' 
ORDER BY
    i.id DESC
LIMIT 10

The result of this is slightly different than your requested result:

+----+-------+
| id | title |
+----+-------+
|  8 | NULL  |
|  7 | NULL  |
|  5 | AAA   |
|  5 | CCC   |
|  4 | DDD   |
|  3 | BBB   |
|  2 | BBB   |
|  1 | NULL  |
+----+-------+

for the RE-modified question (including NULLs):

SELECT
     I.id
    ,max(T.title) as title
FROM images AS i
LEFT JOIN articles_images AS ai ON I.id = ai.image_id
LEFT JOIN topics AS t on ai.article_id = t.id
WHERE i.vender_id = 'model' 
GROUP BY
     I.id
;

+----+-------+
| id | title |
+----+-------+
|  1 | NULL  |
|  2 | BBB   |
|  3 | BBB   |
|  4 | DDD   |
|  5 | CCC   |
|  7 | NULL  |
|  8 | NULL  |
+----+-------+

see: https://rextester.com/LCOBW94449

---

To guarantee you are using the highest article_if I suggest this:

SELECT
     I.id
    ,T.title
FROM ximages AS i
LEFT JOIN (
            SELECT image_id, max(article_id) article_id
            FROM xarticles_images
            GROUP BY image_id
          ) AS ai ON I.id = ai.image_id
LEFT JOIN xtopics AS t on ai.article_id = t.id
WHERE i.vender_id = 'model' 
ORDER BY
    i.id DESC
;

Answer 2

use left join

      SELECT
        i.`id`,
        t.`title`
    FROM
        `images` AS i left join `topics` AS  t on  i.`vender_id` = 'model' 
         and t.`id`=i.article_id