如何在python中用有限的有效数字和千位分隔符格式化整数
[英]How to format an integer in python with limited significant figures AND thousands separators
问题描述
Task: format a (large) integer in python with limited significant figures and thousands separators.
任务：在python中用有限的有效数字和千位分隔符格式化一个（大）整数。
For example, turn例如，转
791075165588
into进入
791,000,000,000
2 条回复
1楼 Roko Mijic 2 已采纳 2020-04-02 11:30:40
The cleanest solution I can find is:我能找到的最干净的解决方案是：
print('{:,}'.format( int( float ('%.3g' % 791075165588 ) ) ) )
Output:输出：
791,000,000,000
Replace the 3 with the desired number of significant figures.将3替换为所需的有效数字位数。
Alternative approach with numpy: numpy 的替代方法：
print( '{:,}'.format( (lambda n, f : np.round(n, f - len(str(abs(int(n)))) ) ) (791075165588 , 3) ) )
2楼 Nicolas Gervais 1 2020-04-02 11:44:34
You seem to have already a solution working for your own purposes.您似乎已经有一个适合您自己目的的解决方案。 If someone would want to choose significant figures from the nearest thousands/millions, rather than choosing the number of significant figures, they could do this:如果有人想从最接近的千位/百万位中选择有效数字，而不是选择有效数字的位数，他们可以这样做：
import numpy as np
mynumber = 791075165588
print(f'Rounding to -9 means billions, for instance {np.round(mynumber, -9):,}')
Rounding to -9 means billions, for instance 791,000,000,000
That was limited to the billions significant figures.这仅限于数十亿的重要数字。
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