Symfony6 使用 memory 用户提供程序登录

Question

I try to login with a symfony's memory user provider with the official doc .

So i make my user with symfony console make:user , i let defaults and chose "no" to using database.

I add my adminuser in security.yaml and some configuration:

security:
  password_hashers:
    Symfony\Component\Security\Core\User\PasswordAuthenticatedUserInterface: "auto"
  providers:
    app_user_provider:
      id: App\Security\UserProvider
    backend_users:
      memory:
        users:
          my:
            {
              password: "$2y$…B3", // i put my true bcrypt generated password
              roles: ["ROLE_ADMIN", "ROLE_SUPER_ADMIN"],
            }
  firewalls:
    dev:
      pattern: ^/(_(profiler|wdt)|css|images|js)/
      security: false
    main:
      lazy: true
      provider: app_user_provider
  access_control:
    - { path: ^/admin, roles: ROLE_ADMIN }
    - { path: ^/profile, roles: ROLE_USER }
when@test:
  security:
    password_hashers:
      Symfony\Component\Security\Core\User\PasswordAuthenticatedUserInterface:
        algorithm: bcrypt
        cost: 4 # Lowest possible value for bcrypt
        time_cost: 3 # Lowest possible value for argon
        memory_cost: 10 # Lowest possible value for argon

I make login action:

    #[Route('/{_locale<%app.supported_locales%>}/login', name: 'my_login')]
    public function login(AuthenticationUtils $authenticationUtils): Response
    {
        // get the login error if there is one
        $error = $authenticationUtils->getLastAuthenticationError();

        // last username entered by the user
        $lastUsername = $authenticationUtils->getLastUsername();
        return $this->render('@MyCore/Core/login.html.twig', [
            'controller_name' => 'CoreController',
            'last_username' => $lastUsername,
            'error'         => $error,
        ]);
    }

With associated form as in the doc:

{% extends '@MyCore/layout-default.html.twig' %}

{% block body %}
    {% if error %}
        <div>{{ error.messageKey|trans(error.messageData, 'security') }}</div>
    {% endif %}

    <form action="{{ path('my_login') }}" method="post">
        <label for="username">Username:</label>
        <input type="text" id="username" name="_username" value="{{ last_username }}"/>

        <label for="password">Password:</label>
        <input type="password" id="password" name="_password"/>

        {# If you want to control the URL the user is redirected to on success
                <input type="hidden" name="_target_path" value="/account"/> #}

        <input type="hidden" name="_csrf_token" value="{{ csrf_token('authenticate') }}">

        <button type="submit">login</button>
    </form>

{% endblock %}

And… Nothing happen. When i try to login, with true user or random false entry, there is no error, no logging, just i go back to "/login" as if nothing happened.

Did i forget something?

Answer 1

There's no firewall configured to use your backend_users user provider.

If you want to use your in-memory users for the main firewall configure it as follows:

security:
  # [..]
  providers:
    backend_users:
      memory:
        users: [] # <- add your users here
  firewalls:
    main:
      lazy: true
      provider: backend_users # <- use the provider here

Answer 2

You are using the app_user_provider but your need to use 2 providers, the app_user_provider and the backend_users provider in same time. To build this you need to use a provider chain ( Symfony Doc ):

# config/packages/security.yaml
security:
    # ...
    providers:
        backend_users:
            # ...

        app_user_provider:
            # ...

        all_users:
            chain:
                providers: ['backend_users', 'app_user_provider']
    firewalls:
        main:
            lazy: true
            provider: all_users # all_users => provider chain

Answer 3

Your problem comes from your security configration. If you need to add two users then you should use a chain, take a look at Symfony docs.