如何从每个排序列表中选择一个数字，以使最小值和最大值之间的差异尽可能小？ [关闭]

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Consider there are k-lists with numbers in an increasing order. Select one number from each list such that the difference between the highest number and lowest number in the output list is minimum:

list 1-1,3,5,9,10
list 2-2,4,6,8
list 3-7,11,12,13

The output should be 5,6,7.

5 is selected from list-l and 6 from list-2 and 7 from list-3

As the difference between highest and lowest number in that list is 2 that is 7-5 consider there are k-lists.

Answer 1

i can solve this in O(N*LogK) , here N is the total number of numbers in the k lists.

1, maintain a pointer for each list, starting from 0.

2, regard current pointers as the numbers you choose, update the answer.

3, select the one with minimum number and increase it by one(as long as it didn't reach the end of that list), if possible, back to step 2, otherwise terminate.

in step 2, and step 3, use heap to maintain the minimum number and maximum, which reduce the time from O(K) to O(LogK) .