在do-while循环中同时检查两个条件

Question

In a tic-tac toe code, I had a do-while loop that checks if one of the players have won..so, something like this

do{
//does some player's input and other things..
}while(!win(x));

now, the big problem is in this loop, it will continue looping until one of the players win. now, how do i check a tie using this same do-while loop?

could I do something like this :

do{
 //still the same checking
}while(!win(x)||!loose(x));

I did try this but it just messed up the code. How could I possibly check a tie in the game?

Thanks

Answer 1

Your logic is slightly off - change the loop condition from:

do{
 //still the same checking
}while(!win(x)||!loose(x));

to:

do{
 //still the same checking
}while(!win(x)&&!loose(x));

or perhaps a more easily understood, but equivalent alternative:

do{
 //still the same checking
}while(!(win(x)||loose(x)));

Answer 2

When you are writing:

!win(x)||!loose(x)

You say not won or not lost and the loop will terminate in the first go. You can use the following:

do{
    //still the same checking
} while (!win(x)&&!loose(x));

or

do{
    //still the same checking
} while (!(win(x)||loose(x)));