Check license using awk and regular expression?

Question

I submit jobs to my university's SGE batch engine and am running a program called COMSOL, which has a limited number of licenses than can be run at a given time. When I submit a job, it sits in a queue for a while until it's my turn. If all of the COMSOL licenses are being used, my job immediately quits and I have to resubmit it, potentially waiting several days before it tries again. I'd like to avoid that. I've created an alias ( comsollicense ) to a program that outputs all of the licensing of COMSOL and its different modules. Among them is a line that looks like this:

Users of COMSOL:  (Total of 7 licenses issued;  Total of 7 licenses in use)

There are other lines in the output that look similar:

Users of WAVEOPTICS:  (Total of 2 licenses issued;  Total of 0 licenses in use)
Users of CHEM:  (Total of 2 licenses issued;  Total of 2 licenses in use)
etc....

In my SGE job script, I want to select the line that starts with "Users of COMSOL" and compare the number of licenses in use to the number issued. If they're the same number, I want it to wait, check again later, and when there is an available license, I want my COMSOL to run. I was thinking something like:

awk '{
    comsollicense
    SOME CODE HERE TO EXTRACT numIssued AND numUsed
    while (numIssued == numUsed){
        sleep 300
        comsollicense
        CODE TO EXTRACT numIssued AND numUSED
    }
}'
comsol -inputfile test.mph

Is this an appropriate approach? I was thinking I could use a regular expression in there, but I am not really familiar with how to program regular expressions. How can I extract the number of licenses issued and the number in use?

Answer 1

Prints the number of issued licenses:

awk '/COMSOL/ { print $6; }'  comsollicense

Prints the number of licenses in use:

awk '/COMSOL/ { print $11; }'  comsollicense

You may use this in a shell-script. Hope this helps.