Python: How to extract data from csv that has NO HEADERS [duplicate]

Question

This question already has an answer here:

• Skip the headers when editing a csv file using Python 3 answers

This is the current code that i have:

with open('some_file.csv', mode='r') as fp:
    reader = csv.reader(fp)
    for row in reader:
        print(row[0])

And I have a csv file that looks something like:

email@email.com,Name
email2@email.com, Name2
and so on...

But when I run this code, it automatically skips the 1st row because it thinks it is a header. I do not want to skip the 1st row and print everything out. How to do that? Thanks.

Answer 1

You can use pandas and set header equal to None :

here is an example :

import pandas as pd

df = pd.read_csv('some_file.csv', header=None)