How to extract files with extension from directories?

Question

I am currently extracting pictures from a large multi-levels directory using the following bash command:

find . -name \*.jpg -exec cp {} /newdir_path_.. \;

However, all pictures are stored under 3 versions:

xxx-LD.jpg
xxx-SD.jpg
xxx.jpg

I just want to extract the xxx.jpg pictures, not the LD and SD... how should my command be modified to perform such extraction?

Answer 1

You can add more tests:

find . -name '*.jpg' -not -name '*-[LS]D.jpg' -exec cp {} /newdir_path_.. \;

-not is a GNU extension; you can use ! -name ! -name instead. In some shells, ! has to be escaped: \\! -name \\! -name .

Answer 2

考虑到文件名仅包含.jpg之前的数字，这也可能对您.jpg ：

find . -iregex '.*/[0-9]*\.jpg$' -exec cp {} /newdir_path_.. \;