increment value in dictionary based on key in another dictionary

Question

I have a masterDict dictionary with keys "1" through "8" with values set to 0

{'1': 0, '2': 0, '3': 0, '4': 0, '5': 0, '6': 0, '7': 0, '8': 0}

I also have anotherDict that i'm using to find the key containing a value closest to another value (i'm doing this multiple times with different values).

An example of one of those other values would be value1 = 900

An example of anotherDict would be:

{'1': 74, '2': 938, '3': 28, '4': 10, '5': 100, '6': 33, '7': 45, '8': 99}

The code i'm using to find the value closest to value1 in anotherDict is:

closestValue1 = key, value = min(anotherDict.items(), key=lambda (_, v): abs(v - value1))

In this case, closestValue1 returns:

{'2': 938}

How do I take this and increment the key 2 value in masterDict by 1?

So, masterDict would then contain:

{'1': 0, '2': 1, '3': 0, '4': 0, '5': 0, '6':0, '7':0, '8': 0}

Answer 1

master_dict = {'1': 0, '2': 0, '3': 0, '4': 0, '5': 0, '6': 0, '7': 0, '8': 0}
another_dict = {'1': 74, '2': 938, '3': 28, '4': 10, '5': 100, '6': 33, '7': 45, '8': 99}
target_val = 900
target_key, _ = min(another_dict.items(), key=lambda x: abs(target_value-x[1])) 
master_dict[target_key]+=1
print (master_dict)