Python: If any variable in list exists, then print the item

Question

I have a list of 0s, named "variables". One of the 0s will become -1 spontaneously, and I'm trying to print the element which does. For example, this is my code:

while True:
    if any(variables):
        print(variables[i])

Now, obviously "i" doesn't correlate to anything, but I'd like it to represent the index of the non-zero variable in the list "variables". Should I enumerate? Is there an easy way to do this with list comprehension? Thank you!

Answer 1

Try

print(list(filter(lambda x: x==-1, variables)))

Answer 2

Do you want to get the index? Outputting the element would be equal to just writing print(-1)

print (variables.index(-1))

Answer 3

Printing the element would just give you -1 .

You can loop through the list:

for e in variables:
    if e != 0:
        # -1 found

By using print(variables.index(-1)) you can also print the spot where -1 was found.