Bash script 'if' statement that calls a function with parameters

Question

I want an if statement in my bash script that does:

if [[ "$v" == "A" || my_func $x $y ]] ; then

but I get the error "conditional binary operator expected". I've tried putting quotes round the parameters in the call to my_func, but still no good. Tried playing around with eval, which didn't help either.

Thanks for any help.

Answer 1

你可以试试：

if [[ "$v" == "A" ]] || my_func $x $y ; then