查询驱动的SSRS矩阵行和列

Question

有没有办法创建一个数据表/矩阵，行和列组是从一个单独的查询/数据集驱动而不是主报表数据？

例如，使用列的“人物”构造： - name - gender - marital_status

我希望矩阵的列始终包含所有“性别”，并且行始终包含所有“婚姻状态”，无论查询的条件如何，行/列的交集都是记录的聚合计数。

例如，查询可能是select * from person where name = 'aaron'

返回的所有记录都是“男性”，但我仍然希望包含“女性”列（其中“女性”列中的所有计数均为0）

我希望输出看起来像：

Marital Status:  ~ Male ~ Female
Single ~ 5 ~ 0
Married ~ 8 ~ 0
Defacto ~ 2 ~ 0
...

我不想做一个虚拟查询，例如：

select 'male' as gender, null as name, null as marital_status
union all 
select 'female' as gender, null as name, null as marital_status
union all
select * from person where [ ...  criteria]

如果可能的话，有3个数据集驱动矩阵会很好......

• “RowData”包含select distinct marital_status from person
• “ColumnData”包含select distinct gender from person ，和
• “MainData”包含`select * from person where [... criteria]

有没有办法让Matrix控件对行/列组使用单独的查询？

Answer 1

为什么这么难？ 想想更容易......在SQL中创建查询，如下所示：

WITH
Gender AS
(
    SELECT 1 AS GenderID, 'Male' AS GenderName
    UNION ALL
    SELECT 2 AS GenderID, 'Female' AS GenderName
),
MartialStatus AS
(
    SELECT 1 AS MartialStatusID, 'Single' AS MStatus
    UNION
    SELECT 2 AS MartialStatusID, 'Married' AS MStatus
),
Persons AS
(
    SELECT 1 AS PersonID, 'John' AS Name, 1 AS GenderID, 2 AS MartialStatusID
    UNION ALL
    SELECT 2 AS PersonID, 'Linda' AS Name, 2 AS GenderID, 1 AS MartialStatusID
    UNION ALL
    SELECT 3 AS PersonID, 'Mike' AS Name, 1 AS GenderID, 1 AS MartialStatusID
    UNION ALL
    SELECT 4 AS PersonID, 'Jenna' AS Name, 2 AS GenderID, 1 AS MartialStatusID  
)
SELECT Gender.GenderName, MartialStatus.MStatus, Persons.PersonID, Persons.Name
FROM Gender
CROSS JOIN MartialStatus
LEFT JOIN Persons ON Persons.GenderID = Gender.GenderID AND 
                     Persons.MartialStatusID = MartialStatus.MartialStatusID

哪个产生结果：

Male    Single   3      Mike
Female  Single   2      Linda
Female  Single   4      Jenna
Male    Married  1      John
Female  Married  NULL    NULL

然后在矩阵映射列和行中的BIDS中：

这里的表达式是=IIF(Sum(Fields!PersonID.Value) IS Nothing, 0, Sum(Fields!PersonID.Value))如果我们没有人，则打印0。 你得到你想要的结果：

它会更容易，更好地表现。