如何使用jQuery或JavaScript重复div？
How to repeat div using jQuery or JavaScript?

因此，您需要div的cloneNode ，因此请尝试这样的操作

var div = document.getElementById('myDiv'),
clone = div.cloneNode(true);
clone.id = "some_id";
document.body.appendChild(clone);

像这样吗 样品小提琴

var lastSection = $('[data-role="page"]:last'); //get the last page probably you can use this to increment the id based on last id
var newSection = lastSection.clone(false);//default is false anyways, if you want to carry over data and events you can use true.
newSection.attr('id','setthenewid');//set the new id
$('div[class^=dydivarr]',newSection).attr('class','newclass'); //set the new class for your divarr
$('.ui-btn-right a',newSection).attr('href','newurlmap');//set the new url map 
lastSection.after(newSection); //place the entire page section in the end

更新：

简单代码有效。 这只是我的错误做法

<script type="text/javascript">

for(var lp=0; lp < 10; lp++)
{
document.write('<div data-role="page" id="page'+lp+'" data-theme="a">');
document.write('  <div data-role="content">');
document.write('    <center>');
document.write('      <h3><a href="#page0" data-role="none"><img src="images/logo.png" /></a></h3>');
document.write('     </center>');
document.write('     <div class="dydivarr+lp+'"> </div>');
document.write('     <br /> ');
document.write('     <div data-role="controlgroup" class="ui-btn-left"> <a href="#page'+(lp-1)+'"     data-role="button">Previous</a> </div>');
document.write('     <div data-role="controlgroup" class="ui-btn-right"> <a href="#page'+(lp+1)+'" data-role="button">Next</a> </div>');
document.write('   </div>');
document.write(' </div>');

}

</script>

谢谢

如何根据选择框值将div复制一定次数？

罗科·C·布尔扬

和

维文·帕利亚斯（Vivin Paliath）

的答案