两个LIKE条件，但先从一个条件检索，然后从另一个条件检索

Question

   SELECT *
   FROM address 
   WHERE name LIKE 'a%' OR name LIKE '% a%' LIMIT 10

该查询检索name s表示与开始a无论是在开始'a%'
或换句话说，中间是'% a%' 。 我如何首先从LIKE 'a%'检索结果
然后按LIKE '% a%' ？。

Answer 1

添加ORDER BY子句，

SELECT *
FROM address
WHERE name LIKE 'a%' OR name LIKE '% a%' 
ORDER BY CASE WHEN name LIKE 'a%' THEN 0 ELSE 1 END
LIMIT 10

Answer 2

这里是：

SELECT t1.*
FROM (
   SELECT *
   FROM address 
   WHERE name LIKE 'a%'
   LIMIT 10
) t1
WHERE t1.name LIKE '% a%' 

Answer 3

一种方法是在查询中添加ORDER BY子句：

ORDER BY IF(name LIKE 'a%',1,2) 

---

像这样：

SELECT *
  FROM address 
 WHERE name LIKE 'a%' OR name LIKE '% a%'
 ORDER BY IF(name LIKE 'a%',1,2) 
 LIMIT 10

---

为了避免对大集合（即地址中的行很多）执行“使用文件排序”操作，并且如果您只想返回10行，则通过限制要排序的行数，看起来更复杂的查询可能会表现更好：

SELECT c.* 
  FROM ( SELECT a.*
           FROM (
                  SELECT *
                    FROM address 
                   WHERE name LIKE 'a%'
                   LIMIT 10 
                ) a
          UNION ALL
         SELECT b.*
           FROM address b
          WHERE b.name LIKE '% a%' AND b.name NOT LIKE 'a%'
          LIMIT 10
       ) c
 ORDER BY c.name LIKE 'a%' DESC
 LIMIT 10

Answer 4

此处可以进行联合查询。 根据MySQL文档

要使UNION结果中的行由每个SELECT依次检索的行集合组成，请在每个SELECT中选择一个附加列用作排序列，并在最后一个SELECT之后添加ORDER BY：

(SELECT 1 AS sort_col, col1a, col1b, ... FROM t1)
UNION
(SELECT 2, col2a, col2b, ... FROM t2) ORDER BY sort_col;

所以对于你的情况

(Select *, 1 as sortcol from addresses where name like 'a%')
 Union
 (Select *, 2 as sortcol from addresses where name like '% a%')
 Order by sortcol

链接： http ： //dev.mysql.com/doc/refman/5.0/en/union.html