我尝试将字符串数组转换为双精度数组,具体取决于从数据库中选择了哪个气象站-一些气象站没有数据,因此整个字符串数组都填充有null(实际上是12个),如果一个他们选择了其中的一个站,但我例外。 我真的没有时间编写很多代码来解决这个问题,因为我必须很快提交我的工作...是否有任何解决方案可以将其捕获并向显示错误的用户显示错误消息? 谢谢!

这是将字符串数组转换为双精度数组的循环

for(int i = 0; i<12; i++)
{   
avMaxTempOptimised[i] = Double.parseDouble(avMaxTempSplit[i]);
avMinTempOptimised[i] = Double.parseDouble(avMinTempSplit[i]);
meanTempOptimised[i] = Double.parseDouble(meanTempSplit[i]);
highestTempOptimised[i] = Double.parseDouble(highestTempSplit[i]);
lowestTempOptimised[i] = Double.parseDouble(lowestTempSplit[i]);
maxWindOptimised[i] = Double.parseDouble(maxWindSplit[i]);
totalRainfallOptimised[i] = Double.parseDouble(totalRainfallSplit[i]);
maxDayRainfallOptimised[i] = Double.parseDouble(maxDayRainfallSplit[i]);
rainDaysOptimised[i] = Double.parseDouble(rainDaysSplit[i]);
totalSunshineOptimised[i] = Double.parseDouble(totalSunshineSplit[i]);
mostSunshineDayOptimised[i] = Double.parseDouble(mostSunshineDaySplit[i]);

avMaxTemp2Optimised[i] = Double.parseDouble(avMaxTemp2Split[i]);
avMinTemp2Optimised[i] = Double.parseDouble(avMinTemp2Split[i]);
meanTemp2Optimised[i] = Double.parseDouble(meanTemp2Split[i]);
highestTemp2Optimised[i] = Double.parseDouble(highestTemp2Split[i]);
lowestTemp2Optimised[i] = Double.parseDouble(lowestTemp2Split[i]);
maxWind2Optimised[i] = Double.parseDouble(maxWind2Split[i]);
totalRainfall2Optimised[i] = Double.parseDouble(totalRainfall2Split[i]);
maxDayRainfall2Optimised[i] = Double.parseDouble(maxDayRainfall2Split[i]);
rainDays2Optimised[i] = Double.parseDouble(rainDays2Split[i]);
totalSunshine2Optimised[i] = Double.parseDouble(totalSunshine2Split[i]);
mostSunshineDay2Optimised[i] = Double.parseDouble(mostSunshineDay2Split[i]);
}

===============>>#1 票数:0

如果您在外部尝试/捕获for循环,则将停止处理循环的其余部分。 只要不介意数组中剩余的未分配值,在for循环内尝试/捕获操作可能会更接近。 最好将优化数组更改为Double []类型,如下所示:

for(int i = 0; i<12; i++)
{   
avMaxTempOptimised[i] = safeDouble(avMaxTempSplit[i]);
avMinTempOptimised[i] = safeDouble(avMinTempSplit[i]);
meanTempOptimised[i] = safeDouble(meanTempSplit[i]);
highestTempOptimised[i] = safeDouble(highestTempSplit[i]);
lowestTempOptimised[i] = safeDouble(lowestTempSplit[i]);
maxWindOptimised[i] = safeDouble(maxWindSplit[i]);
totalRainfallOptimised[i] = safeDouble(totalRainfallSplit[i]);
maxDayRainfallOptimised[i] = safeDouble(maxDayRainfallSplit[i]);
rainDaysOptimised[i] = safeDouble(rainDaysSplit[i]);
totalSunshineOptimised[i] = safeDouble(totalSunshineSplit[i]);
mostSunshineDayOptimised[i] = safeDouble(mostSunshineDaySplit[i]);

avMaxTemp2Optimised[i] = safeDouble(avMaxTemp2Split[i]);
avMinTemp2Optimised[i] = safeDouble(avMinTemp2Split[i]);
meanTemp2Optimised[i] = safeDouble(meanTemp2Split[i]);
highestTemp2Optimised[i] = safeDouble(highestTemp2Split[i]);
lowestTemp2Optimised[i] = safeDouble(lowestTemp2Split[i]);
maxWind2Optimised[i] = safeDouble(maxWind2Split[i]);
totalRainfall2Optimised[i] = safeDouble(totalRainfall2Split[i]);
maxDayRainfall2Optimised[i] = safeDouble(maxDayRainfall2Split[i]);
rainDays2Optimised[i] = safeDouble(rainDays2Split[i]);
totalSunshine2Optimised[i] = safeDouble(totalSunshine2Split[i]);
mostSunshineDay2Optimised[i] = safeDouble(mostSunshineDay2Split[i]);
}


...

safeDouble( String str){
return str== null ? null : Double.parseDouble(str);
}

在阅读优化数组的地方添加快速的空检查,您会很聪明。

  ask by Andrei Ivanov translate from so

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