在MDX中选择3个月内的平均销售量

Question

我对以下查询有疑问：

月与月比较。 将当前月份的销售额与其他三个数字进行比较： 前一个月。 b。 前三个月的平均值。 C。 前三个月之前的三个月期间的平均值。

这是数据库/多维数据集的结构：

WITH MEMBER [Measures].[Current Month] AS 
    [Measures].[PIZZA SALES Count]
MEMBER [Measures].[Previous Month] AS
        AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(1)},[Measures].[PIZZA SALES Count]])

MEMBER [Measures].[3 Months] AS
        ((AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(1)},[Measures].[PIZZA SALES Count]]) +
         AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(2)},[Measures].[PIZZA SALES Count]]) +
         AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(3)},[Measures].[PIZZA SALES Count]]))/3)   

MEMBER [Measures].[6 Months] AS
        ((AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(4)},[Measures].[PIZZA SALES Count]]) +
         AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(5)},[Measures].[PIZZA SALES Count]]) +
         AVG({[PIZZA SALES].[Time ID].Children * [TIME].    [Month].CurrentMember.lag(6)},[Measures].[PIZZA SALES Count]]))/3)

    SELECT
    {
        [Measures].[Current Month],
        [Measures].[Previous Month],
        [Measures].[3 Months],
        [Measures].[6 Months]
    }
    ON COLUMNS,
    {
        [TIME].[Month].&[12]
    } ON ROWS
FROM [Pizza Place Cube];

该查询的结果如下：

下面的SQL脚本返回正确的结果：

SELECT
(SELECT COUNT(*) FROM PIZZA_SALES WHERE TimeID IN (
SELECT TimeID FROM TIME WHERE Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT     MAX(TimeID) FROM PIZZA_SALES))) AND
        Year = (SELECT Year FROM TIME WHERE TIMEID = (SELECT MAX(TimeID) FROM     PIZZA_SALES)))) AS 'CURRENT MONTH',
(SELECT COUNT(*) FROM PIZZA_SALES WHERE TimeID IN (
SELECT TimeID FROM TIME WHERE Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT     MAX(TimeID) FROM PIZZA_SALES)))-1 AND
        Year = (SELECT Year FROM TIME WHERE TIMEID = (SELECT MAX(TimeID) FROM     PIZZA_SALES)))) AS 'PREVIOUS MONTH',
(SELECT COUNT(*)/3 FROM PIZZA_SALES WHERE TimeID IN (
SELECT TimeID FROM TIME WHERE
        Year = (SELECT Year FROM TIME WHERE TIMEID = (SELECT MAX(TimeID) FROM     PIZZA_SALES)) AND
        (Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT MAX(TimeID) FROM     PIZZA_SALES)))-1 OR
        Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT MAX(TimeID) FROM     PIZZA_SALES)))-2 OR
        Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT MAX(TimeID) FROM     PIZZA_SALES)))-3))) AS '3 MONTHS',
(SELECT COUNT(*)/3 FROM PIZZA_SALES WHERE TimeID IN (
SELECT TimeID FROM TIME WHERE
        Year = (SELECT Year FROM TIME WHERE TIMEID = (SELECT MAX(TimeID) FROM     PIZZA_SALES)) AND
        (Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT MAX(TimeID) FROM     PIZZA_SALES)))-4 OR
        Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT MAX(TimeID) FROM     PIZZA_SALES)))-5 OR
        Month = (SELECT Month FROM TIME WHERE TIMEID = ((SELECT MAX(TimeID) FROM     PIZZA_SALES)))-6))) AS '6 MONTHS';

SQL查询返回的期望结果如下：

请帮忙，我在互联网上尝试了许多不同的解决方案，但是它们没有返回正确的结果。

Answer 1

以下查询应返回您想要的内容：

WITH MEMBER [Measures].[Current Month] AS 
    [Measures].[PIZZA SALES Count]
MEMBER [Measures].[Previous Month] AS
        ([TIME].[Month].CurrentMember.Lag(1),
         [Measures].[PIZZA SALES Count])

MEMBER [Measures].[3 Months] AS
        AVG([TIME].[Month].CurrentMember.Lag(3) : [TIME].[Month].CurrentMember.Lag(1),
            [Measures].[PIZZA SALES Count])   

MEMBER [Measures].[6 Months] AS
        AVG([TIME].[Month].CurrentMember.Lag(6) : [TIME].[Month].CurrentMember.Lag(4),
            [Measures].[PIZZA SALES Count])   

    SELECT
    {
        [Measures].[Current Month],
        [Measures].[Previous Month],
        [Measures].[3 Months],
        [Measures].[6 Months]
    }
    ON COLUMNS,
    {
        [TIME].[Month].&[12]
    } ON ROWS
FROM [Pizza Place Cube]

请注意， Avg需要一个集合作为第一个参数，并且冒号构造会建立一个集合，该集合从冒号之前的成员开始，再到冒号之后的成员结束。