在python 3.3中将带有空格的字符串转换为html url

Question

我正在尝试将带空格的YQL字符串转换为html代码。

这是我正在使用的YQL字符串：

select * from yahoo.finance.historicaldata where symbol in ("MSFT", "AAPL") and startDate = "2010-10-01" and endDate = "2010-10-05"

这是需要出现的网址代码：

http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.historicaldata%20where%20symbol%20in%20(%22MSFT%22%2C%20%22AAPL%22)%20and%20startDate%20%3D%20%222010-10-01%22%20and%20endDate%20%3D%20%222010-10-05%22&format=json&diagnostics=true&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys&callback=

我一直试图用urllib.parse.urlencode做这个，但没有运气。

我可以起床“ http://query.yahooapis.com/v1/public/yql ？” 但之后它开始崩溃。 是否有一种pythonesque方式来做到这一点，我只是缺少？

谢谢！

Answer 1

import urllib

url_start = "http://query.yahooapis.com/v1/public/yql?q="
url_end = "&format=json&diagnostics=true&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys&callback="

你可以将字符串编码为dict，如下所示：

d = {'select * from yahoo.finance.historicaldata where symbol in ("MSFT", "AAPL") and startDate':'"2010-10-01"', 'and endDate':'"2010-10-05"'}

encode_url = urllib.urlencode(d)

#output is:
'select+%2A+from+yahoo.finance.historicaldata+where+symbol+in+%28%22MSFT%22%2C+%22AAPL%22%29+and+startDate=%222010-10-01%22&and+endDate=%222010-10-05%22'

url = url_start + encode_url + url_end

Answer 2

>>> import urllib
>>> urllib.quote('http://www.example.com/déjà-vu/example two.html')
'http%3A//www.example.com/d%C3%A9j%C3%A0-vu/example%20two.html'