bash变量不适用于脚本中的ex

Question

我的bash脚本有点问题。

 #!/bin/bash
 ex xxx.html << "HERE"
 1,$s/\(foo\)/$1\1/
 wq
 HERE

这只是我脚本的一小部分。 当我运行它时，这是输出。

$1foo

有什么办法解决这个问题，所以$ 1将成为脚本的参数？

谢谢！

Answer 1

尝试将"HERE"替换为HERE （未引用）。 同样， 1,$s变成1,\\$s 。

Here Documents
   This type of redirection instructs the shell to  read  input  from  the
   current source until a line containing only delimiter (with no trailing
   blanks) is seen.  All of the lines read up to that point are then  used
   as the standard input for a command.

   The format of here-documents is:

          <<[-]word
                  here-document
          delimiter

   No  parameter expansion, command substitution, arithmetic expansion, or
   pathname expansion is performed on word.  If any characters in word are
   quoted,  the  delimiter is the result of quote removal on word, and the
   lines in the here-document are not expanded.  If word is unquoted,  all
   lines  of  the here-document are subjected to parameter expansion, com-
   mand substitution, and arithmetic expansion.  In the latter  case,  the
   character  sequence  \<newline> is ignored, and \ must be used to quote
   the characters \, $, and `.

   If the redirection operator is <<-, then all leading tab characters are
   stripped  from  input  lines  and  the line containing delimiter.  This
   allows here-documents within shell scripts to be indented in a  natural
   fashion.

重击手册。

Answer 2

将"HERE"替换为HERE （不带引号），将1,$替换为1,\\$或%

您可以如下编写脚本：

#!/bin/bash
ex xxx.html <<-HERE
%s/foo/$1&/
x
HERE

尽管您还可以构建一个较小的脚本：

#!/bin/bash
sed -i "s/foo/$1&/g" xxx.html

Answer 3

尝试这个。

#!/bin/bash
(echo '1,$s/\(foo\)/'"$1"'\1/'; echo 'wq') | ex xxx.html

单引号中的1,$s/\\(foo\\)/ ，双引号中的$1相邻（因此，shell替换参数），单引号中的\\1/相邻。