[英]TSQL Parse XML in Stored Procedure
我有4个表,其中包含各种数据。
表1包含问题表2包含组表3包含选项表4包含作业应用程序,其中包含“个人资料数据”列
概要文件数据已生成并转换为XML,并存储在表4的profileData列中。其格式如下:
<proficiencies>
<question>
<questionID>2</questionID>
<questionGroup>2</questionGroup>
<questionOptions>
<option>19</option>
<option>20</option>
<option>31</option>
</questionOptions>
</question>
<question>
<questionID>1</questionID>
<questionGroup>1</questionGroup>
<questionOptions>
<option>20</option>
<option>29</option>
<option>21</option>
</questionOptions>
</question>
<question>
<questionID>3</questionID>
<questionGroup>2</questionGroup>
<questionOptions>
<option>18</option>
<option>29</option>
</questionOptions>
</question>
</proficiencies>
现在,我正在创建一个页面,在该页面上需要使用所有选择的设置来重新创建作业应用程序。 创建XML时,我使用的是与实际问题和信息相关的ID号。
找出现在这些ID号是什么的最好方法是什么? 我认为最好在存储过程中执行此操作,因为如果我在用javascript解析时执行了此操作,则它将有很多数据库调用。
只是不确定如何最好地执行此操作或更改数据库的结构。
在示例中,我需要找出问题所在,问题ID = 2等。
有一个更好的方法吗?
我认为您正在寻找XQuery 。
下面的示例解析您的XML并加入问题表。 它使用nodes() , query()和value()方法。
with MyXML
as
(
select
1 as MyXMLDataID
,cast('
<proficiencies>
<question>
<questionID>2</questionID>
<questionGroup>2</questionGroup>
<questionOptions>
<option>19</option>
<option>20</option>
<option>31</option>
</questionOptions>
</question>
<question>
<questionID>1</questionID>
<questionGroup>1</questionGroup>
<questionOptions>
<option>20</option>
<option>29</option>
<option>21</option>
</questionOptions>
</question>
<question>
<questionID>3</questionID>
<questionGroup>2</questionGroup>
<questionOptions>
<option>18</option>
<option>29</option>
</questionOptions>
</question>
</proficiencies>' as xml) as MyXMLData),
MyQuestionGroups
as
(
select 1 as questionGroup, 'Education' as questionGroup_description
union
select 2 as questionGroup, 'Experience' as questionGroup_description
),
MyQuestions
as
(
select 1 as questionGroup, 1 as questionID, 'High school attendance' as question
union
select 2 as questionGroup, 2 as questionID, 'Alchemy experience' as question
union
select 2 as questionGroup, 3 as questionID, 'Arbitrage experience' as question
),
MyOptions
as
(
select 18 as optionID, '1 year' as option_description
union
select 19 as optionID, '2 year' as option_description
union
select 20 as optionID, '3 years' as option_description
union
select 21 as optionID, '4 year' as option_description
union
select 29 as optionID, '5 year' as option_description
union
select 31 as optionID, '6 years' as option_description
)
SELECT MyXML.MyXMLDataID
,t1.questionID.query('.') as questionID_node
,q.question
FROM MyXML
CROSS APPLY MyXMLData.nodes('/proficiencies/question/questionID') as t1(questionID)
INNER JOIN MyQuestions q
on q.questionID = t1.questionID.value('.', 'int')
它返回以下结果:
-----------------------------------------------
MyXMLDataID questionID_node question
-----------------------------------------------
1 <questionID>2</questionID> Alchemy experience
1 <questionID>1</questionID> High school attendance
1 <questionID>3</questionID> Arbitrage experience
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.