具有超过四十列的UNPIVOT数据

Question

测试数据

DECLARE @T table
( ClientID INT, Dated DateTime,Value1 varchar(10),Value2 varchar(10),
  Value3 varchar(10),Value4 varchar(10),Value5 varchar(10),Value6 varchar(10)
  ,Value7 varchar(10),Value8 varchar(10),Value9 varchar(10)
)

INSERT INTO @T values
(1,'2014-01-06 16:27:47.440','High','Low','Medium','High','Medium','Low','Medium','High','Low'),
(2,'2014-01-06 16:27:47.440','Medium','High','Low','Medium','High','Low','Medium','Low','Medium'),
(1,'2014-01-01 16:27:47.440','Medium','Low','High','Medium','Low','Medium','High','Low','Medium')

SELECT * FROM @T

╔══════════╦═════════════════════════╦════════╦════════╦════════╦════════╦════════╦════════╦════════╦════════╦════════╗
║ ClientID ║          Dated          ║ Value1 ║ Value2 ║ Value3 ║ Value4 ║ Value5 ║ Value6 ║ Value7 ║ Value8 ║ Value9 ║
╠══════════╬═════════════════════════╬════════╬════════╬════════╬════════╬════════╬════════╬════════╬════════╬════════╣
║        1 ║ 2014-06-01 16:27:47.440 ║ High   ║ Low    ║ Medium ║ High   ║ Medium ║ Low    ║ Medium ║ High   ║ Low    ║
║        2 ║ 2014-06-01 16:27:47.440 ║ Medium ║ High   ║ Low    ║ Medium ║ High   ║ Low    ║ Medium ║ Low    ║ Medium ║
║        1 ║ 2014-01-01 16:27:47.440 ║ Medium ║ Low    ║ High   ║ Medium ║ Low    ║ Medium ║ High   ║ Low    ║ Medium ║
╚══════════╩═════════════════════════╩════════╩════════╩════════╩════════╩════════╩════════╩════════╩════════╩════════╝

我的查询

SELECT TOP 1 
        B.Value1 AS Historical_Value1, A.Value1 AS Recent_Value1
    ,   B.Value2 AS Historical_Value2, A.Value2 AS Recent_Value2
    ,   B.Value3 AS Historical_Value3, A.Value3 AS Recent_Value3
    ,   B.Value4 AS Historical_Value4, A.Value4 AS Recent_Value4
    ,   B.Value5 AS Historical_Value5, A.Value5 AS Recent_Value5
    ,   B.Value6 AS Historical_Value6, A.Value6 AS Recent_Value6
    ,   B.Value7 AS Historical_Value7, A.Value7 AS Recent_Value7
    ,   B.Value8 AS Historical_Value8, A.Value8 AS Recent_Value8
    ,   B.Value9 AS Historical_Value9, A.Value9 AS Recent_Value9
FROM @T A INNER JOIN @T B
ON A.ClientID = B.ClientID
WHERE B.Dated < A.Dated
ORDER BY A.Dated DESC, B.Dated DESC

正如你所看到的那样，我正在为所有值和之前录制的录音提取最新的录音。 最近的价值观和历史价值。 以下列格式返回数据。

当前输出

╔═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╦═══════════════════╦═══════════════╗
║ Historical_Value1 ║ Recent_Value1 ║ Historical_Value2 ║ Recent_Value2 ║ Historical_Value3 ║ Recent_Value3 ║ Historical_Value4 ║ Recent_Value4 ║ Historical_Value5 ║ Recent_Value5 ║ Historical_Value6 ║ Recent_Value6 ║ Historical_Value7 ║ Recent_Value7 ║ Historical_Value8 ║ Recent_Value8 ║ Historical_Value9 ║ Recent_Value9 ║
╠═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╬═══════════════════╬═══════════════╣
║ Medium            ║ High          ║ Low               ║ Low           ║ High              ║ Medium        ║ Medium            ║ High          ║ Low               ║ Medium        ║ Medium            ║ Low           ║ High              ║ Medium        ║ Low               ║ High          ║ Medium            ║ Low           ║
╚═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╩═══════════════════╩═══════════════╝

期望的输出

但是我想将UNPIVOT的数据显示为Follows，我在SO上看到了很多问题但是它们似乎都不符合我的要求。 任何指针都欢迎任何建议，谢谢。

╔════════╦════════════╦════════╗
║ Values ║ Historical ║ Recent ║
╠════════╬════════════╬════════╣
║ Value1 ║ High       ║ Medium ║
║ Value2 ║ Low        ║ Low    ║
║ Value3 ║ Medium     ║ High   ║
║ Value4 ║ High       ║ Medium ║
║ Value5 ║ High       ║ Medium ║
╚════════╩════════════╩════════╝

Answer 1

这将是一种方法：

;WITH up AS 
(
    SELECT * FROM @T 
    UNPIVOT
    (
         val FOR n IN (Value1,value2,value3,value4,value5,value6,value7,value8,value9)
    ) as pv
)
SELECT 
    A.ClientID,
    A.Dated,
    A.n as Values,
    A.val as Recent,
    B.val as History
FROM
    up as A
    JOIN up as B
        ON A.ClientID = B.ClientID
        AND A.n = B.n
WHERE B.Dated < A.Dated
ORDER BY 
    A.Dated DESC, B.Dated DESC