SQlite Android没有这样的表列student.studentId

Question

我想我几乎花时间在网上搜索可能的解决方案。 我成功地插入了一个学生和一个学科，但是当从两个表中获取数据时，它将导致程序崩溃并显示错误“没有这样的列”。

请帮我。

建立表格

private static final String CREATE_TABLE_SUBJECT = "CREATE TABLE "
        + TABLE_SUBJECT + "(" + SUBJECT_ID + " INTEGER PRIMARY KEY," + SUBJECT_NAME
        + " TEXT," + SUBJECT_SCHEDULE + " TEXT," + SUBJECT_FILELOCATION
        + " TEXT" + ")";

private static final String CREATE_TABLE_STUDENT = "CREATE TABLE "
        + TABLE_STUDENT + "(" + SUBJECT_ID + " INTEGER PRIMARY KEY," + STUDENT_NAME
        + " TEXT" + ")";

private static final String CREATE_TABLE_FUSION = "CREATE TABLE "
        + TABLE_FUSION + "(" + FUSION_ID + " INTEGER PRIMARY KEY," + SUBJECT_ID
        + " INTEGER," + STUDENT_ID +" INTEGER" + ")";

我的查询显示两个表中的数据

public List<Student> getAllStudnetsBySubject(long id) {
    List<Student> subject = new ArrayList<Student>();


    String selectQuery = "SELECT  * FROM " + TABLE_STUDENT + " students, "
            + TABLE_SUBJECT + " subjects, " + TABLE_FUSION + " fusions WHERE subjects."
            + SUBJECT_ID + " = '" + id + "'" + " AND subjects." + SUBJECT_ID
            + " = " + "fusions." + FUSION_ID + " AND students." + STUDENT_ID + " = "
            + "fusions." + FUSION_ID;



    SQLiteDatabase db = this.getReadableDatabase();
    Cursor c = db.rawQuery(selectQuery, null);


    if (c.moveToFirst()) {
        do {
            Student s = new Student();
            s.setStudentId(c.getInt((c.getColumnIndex(STUDENT_ID))));
            s.setStudentName((c.getString(c.getColumnIndex(STUDENT_NAME))));
            subject.add(s);


        } while (c.moveToNext());
    }

    return subject;
}

LOGCAT错误

02-27 07:00:32.938: E/DatabaseHelper(20727): SELECT  * FROM student students, subject subjects, fusion fusions WHERE subjects.subject_id = '1' AND subjects.subject_id = fusions.id AND students.student_id = fusions.id
02-27 07:00:32.948: E/SQLiteLog(20727): (1) no such column: students.student_id

Answer 1

String EntryA =String.valueOf( db.getentry("Ravirrrr", "KEY_Team_Name"));

更改为

String EntryA =String.valueOf( db.getentry("Ravirrrr", "_Team_Name"));

KEY_Team_Name是sqlite助手中的变量，其值包含列名"_Team_Name" 。 您不需要文字字符串"KEY_Team_Name" 。

Answer 2

好吧，您没有将student_id添加到student表中：

private static final String CREATE_TABLE_STUDENT = "CREATE TABLE "
        + TABLE_STUDENT + "(" + SUBJECT_ID + " INTEGER PRIMARY KEY," + STUDENT_NAME
        + " TEXT" + ")";

您需要修改并添加它：

private static final String CREATE_TABLE_STUDENT = "CREATE TABLE "
        + TABLE_STUDENT + "(" + STUDENT_ID + " INTEGER PRIMARY KEY," + SUBJECT_ID + " INTEGER PRIMARY KEY," + STUDENT_NAME
        + " TEXT" + ")";

Answer 3

看起来您犯了一个简单的复制粘贴错误。 更改此：

private static final String CREATE_TABLE_STUDENT = "CREATE TABLE "
    + TABLE_STUDENT + "(" + SUBJECT_ID + " INTEGER PRIMARY KEY," + STUDENT_NAME
    + " TEXT" + ")";

对此：

private static final String CREATE_TABLE_STUDENT = "CREATE TABLE "
    + TABLE_STUDENT + "(" + STUDENT_ID + " INTEGER PRIMARY KEY," + STUDENT_NAME
    + " TEXT" + ")";

换句话说，只需将SUBJECT_ID更改为STUDENT_ID。

Answer 4

看起来，当您为学生表编写代码时，您从“主题”表中复制了代码并对其进行了修改，但您忘记将“主题ID”列修改为“学生ID”。 因此，Student表中没有Student_ID的错误提示。 使用以下更新的代码，

private static final String CREATE_TABLE_SUBJECT = "CREATE TABLE " + TABLE_SUBJECT + "(" 
        + SUBJECT_ID + " INTEGER PRIMARY KEY," 
        + SUBJECT_NAME + " TEXT," 
        + SUBJECT_SCHEDULE + " TEXT," 
        + SUBJECT_FILELOCATION + " TEXT" 
        + ")";

private static final String CREATE_TABLE_STUDENT = "CREATE TABLE " + TABLE_STUDENT + "(" 
        + STUDENT_ID + " INTEGER PRIMARY KEY,"  // Change here 
        + STUDENT_NAME + " TEXT" 
        + ")";

private static final String CREATE_TABLE_FUSION = "CREATE TABLE " + TABLE_FUSION + "(" 
        + FUSION_ID + " INTEGER PRIMARY KEY," 
        + SUBJECT_ID + " INTEGER," 
        + STUDENT_ID +" INTEGER" 
        + ")";