根据另一个列表过滤列表

Question

我想根据drop项目过滤data 。

data = [
    ['Basket', 'NBA ET', 'Kobe'],
    ['Basket', 'NCAA', 'Shaq'],
    ['Basket', 'ENG', 'Shaq'],
]
drop = ['NBA', 'NCAA']

而且因为我也希望将NBA ET的名单也排除在外，所以它必须超越：

filtered = [d for d in data if d[1] not in drop]   # assume d[1] will hold

我需要的是：

# pseudocode
filtered = [d for d in data if _ not in d[1] for _ in drop]

但我永远不记得语法。

作为记录， filtered应显示[['Basket', 'ENG', 'Shaq']]

Answer 1

您可以使用any()并在空白处分割字符串：

filtered = [d for d in data if not any(dropped in d[1].split() for dropped in drop)]

如果您drop一个set ，只需测试一个交集：

drop = set(drop)

filtered = [d for d in data if not drop.intersection(d[1].split())]

drop越大，后者应越有表现。

演示：

>>> data = [
...     ['Basket', 'NBA ET', 'Kobe'],
...     ['Basket', 'NCAA', 'Shaq'],
...     ['Basket', 'ENG', 'Shaq'],
... ]
>>> drop = ['NBA', 'NCAA']
>>> [d for d in data if not any(dropped in d[1].split() for dropped in drop)]
[['Basket', 'ENG', 'Shaq']]
>>> drop = set(drop)
>>> [d for d in data if not drop.intersection(d[1].split())]
[['Basket', 'ENG', 'Shaq']]

Answer 2

[row for row in data if not any(league in row[1].split() for league in drop)]
# [['Basket', 'ENG', 'Shaq']]