检查是否已在python中按下按钮？

Question

码：

import sys
from tkinter import *

credit = 0
coins = 0
choice = 0


credit1 = 0
coins = 0
prices = [200,150,160,50,90]
item = 0
i = 0
temp=0
n=0
choice1 = 0
choice2 = 0

credit1 = 0
coins = 0
prices = [200,150,160,50,90]
item = 0
i = 0
temp=0
n=0
choice1 = 0
choice2 = 0

def insert():
    insert = Tk()

    insert.geometry("450x250")
    iLabel = Label(insert, text="Enter coins.[Press Buttons]").grid(row=1, column=1)

    tenbutton = Button(insert, text="10p").grid(row=2, column=1)
    twentybutton = Button(insert, text="20p").grid(row=3, column=1)
    fiftybutton = Button(insert, text="50p").grid(row=4, column=1)
    poundbutton = Button(insert, text="£1").grid(row=5, column=1)

我正在创建一个模拟自动售货机的程序。 如果按下按钮，我如何告诉Python“检查”？ 用伪代码将是：

if tenbutton is pressed:
   Add 10p to credit

我如何在Python中编写“如果按下tenbutton”？ 先感谢您。

Answer 1

您可以将command添加到Tkinter Button小部件，该command将回调函数：

def tenbuttonCallback():
    global credit
    credit += 10

tenbutton = Button(insert, text="10p", command=tenbuttonCallback)
tenbutton.grid(row=2, column=1)

请参阅： http ： //effbot.org/tkinterbook/button.htm

Answer 2

很简单，定义一个在按下按钮后将调用的函数。 像这样：

def addCredit():
    global credit
    credit+=10

然后将此简单功能分配给您的按钮：

tenbutton = Button(insert, text="10p", command=addCredit).grid(row=2, column=1)

顺便说一句，您的代码在某处严重要求一个class 。 使用这么多的全局变量通常不是一个好习惯。 另一个nitpick from tkinter import * ，它破坏了可读性。 我建议import tkinter as tk 。

Answer 3

from tkinter import *
import tkinter
import tkinter.messagebox

root = Tk()


def fun(arg):
    if arg == 1:
        tkinter.messagebox.showinfo("button 1", "button 1 used")
    elif arg == 2:
        tkinter.messagebox.showinfo("button 2", "button 2 used")
    elif arg == 3:
        tkinter.messagebox.showinfo("button 3", "button 3 used")
    elif arg == 4:
        tkinter.messagebox.showinfo("button 4", "button 4 used")


b1 = Button(root, text="Quit1", command=lambda: fun(1))
b1.pack()
b2 = Button(root, text="Quit2", command=lambda: fun(2))
b2.pack()
b3 = Button(root, text="Quit3", command=lambda: fun(3))
b3.pack()
b4 = Button(root, text="Quit4", command=lambda: fun(4))
b4.pack()

root.mainloop()