Ajax获取带有JQuery错误的请求

Question

我正在尝试使用get请求调用php脚本，并使用datatheaddress数据，但是结果向我显示了im调用页面的源代码。

我正在调用的页面在这里这是我的ajax函数，它将获取此页面

    $( document ).ready(function() {
        var address = document.getElementById("address");

     $.ajax({
      url: '/r10database/checkSystem/ManorWPG.php',
      type: 'GET',
      data: 'theaddress='+address.value,
      cache: false,
      success: function(output) 
      {
          alert('success, server says '+output);
      }, error: function()
      {
        alert('Something went wrong, saving system failed');
      }
   });



    });

Answer 1

$( document ).ready(function() {
    var address = document.getElementById("address");

 $.ajax({
  url: '/r10database/checkSystem/ManorWPG.php',
  type: 'GET',
  data: 'theaddress='+address.value,
  cache: false,
  success: function(output) 
  {
      alert('success, server says '+output);
  }, error: function(error)
  {
    alert (error); // this is the change from the question
  }
});
});

Answer 2

用大括号将dataType作为json

data: {theaddress:address.value},
dataType:'json',
success: function(output) 
{
    alert('success, server says '+output);
}, error: function(xhr)
{
   alert (xhr.status);
}

并以$ _GET ['theaddress']的形式获取ManorWPG.php中的数据

**如果失败，请共享xhr.status。