PHP代码解析错误，可能只是格式错误

Question

我试图在通过PHP代码显示的表中显示图像，但是这给了我一个错误，我不知道在哪里。

echo '<tr><td align="left" valign="top" class="description"> . "<img src='images/" . $product_data["mainImageThumbnail"] . "' alt='Product image' />
    <p><a href="main.php?prodid=' . $product["product_id"] . '">' . $product["name"] . '</a>
    <br /> $products_data["description"] </p>
    <a href="#">Remove</a>
    </td> ';

Answer 1

问题是PHP与HTML的串联

echo '<tr><td align="left" valign="top" class="description">
<img src="images/' . $product_data["mainImageThumbnail"] . '" alt="Product image" />
<p><a href="main.php?prodid=' . $product["product_id"] . '">' . $product["name"] . '</a>
<br />'. $products_data["description"] .'</p>
<a href="#">Remove</a>
</td> ';

Answer 2

echo '<tr>
    <td align="left" valign="top" class="description">
        <img src="images/' . $product_data["mainImageThumbnail"] . '" alt="Product image"/>
        <p>
            <a href="main.php?prodid=' . $product["product_id"] . '">' . $product["name"] . '</a>
            <br/>' .
            $products_data["description"] . '
        </p>
    <a href="#">Remove</a>
</td> ';