[英]Print function for class c++
我想为 AutoData 类编写一个打印函数,其中包含有关汽车的信息。 使用此打印功能,我希望打印出一个包含许多不同类对象的向量。 我已经为对象的每个元素编写了 get 函数,但我仍然有点不确定如何使用这些函数来编写一个函数以按以下格式打印数据:
mpg:cylinders:displacement:horsepower:weight:acceleration:modelYear:origin:carName
例如:
10.0:8:360.0:215.0:4615.:14.0:70:1:ford f250
10.0:8:307.0:200.0:4376.:15.0:70:1:chevy c20
11.0:8:318.0:210.0:4382.:13.5:70:1:dodge d200
班级是:
#include <string>
#include <vector>
#include <iostream>
using namespace std;
class AutoData {
public:
AutoData()
{
mpg = 0;
cylinders = 0;
displacement = 0;
horsepower = 0;
weight = 0;
acceleration = 0;
modelYear = 0;
origin = 0;
carName = "";
}
AutoData( const AutoData & rhs)
{
setAuto(rhs.mpg, rhs.cylinders, rhs.displacement, rhs.horsepower, rhs.weight, rhs.acceleration, rhs.modelYear, rhs.origin, rhs.carName);
}
void setAuto(float mp, int cy, float di, float ho, float we, float ac, int mo, int o, string ca)
{
mpg = mp;
cylinders = cy;
displacement = di;
horsepower = ho;
weight = we;
acceleration = ac;
modelYear = mo;
origin = o;
carName = ca;
}
const float & getmpg( ) const
{
return mpg;
}
const int & getcylinders( ) const
{
return cylinders;
}
const float & getdisplacement( ) const
{
return displacement;
}
const float & gethorsepower( ) const
{
return horsepower;
}
const float & getweight( ) const
{
return weight;
}
const float & getacceleration( ) const
{
return acceleration;
}
const int & getmodelYear( ) const
{
return modelYear;
}
const int & getorigin( ) const
{
return origin;
}
const string & getcarName( ) const
{
return carName;
}
bool operator == (const AutoData & rhs ) const
{
if( getmpg( ) == rhs.getmpg( ) )
{
return gethorsepower( ) == rhs.gethorsepower( );
}
else
{
return false;
}
}
bool operator > ( const AutoData & rhs ) const
{
if( rhs.getmpg( ) > getmpg( ) )
{
return true;
}
else if( getmpg( ) == rhs.getmpg( ) )
{
if( rhs.gethorsepower( ) > gethorsepower( ) )
{
return true;
}
}
else
{
return false;
}
}
private:
float mpg;
int cylinders;
float displacement;
float horsepower;
float weight;
float acceleration;
int modelYear;
int origin;
string carName;
};
任何人都可以提供的任何帮助/建议将不胜感激!! 谢谢
如果您希望能够执行std::cout << AutoData();
,您需要重载输出流运算operator<<
:
std::ostream& operator<< (std::ostream &out, AutoData const& data) {
out << data.getmpg() << ':';
out << data.getcylinders() << ':';
// and so on...
return out;
}
此函数不是成员函数,并且由于每个属性都有 getter,因此不必将此函数声明为类的friend
。
然后你可以这样做:
AutoData myAuto;
std::cout << myAuto << '\n';
你都尝试了些什么? 我的方法是重载operator<<
,例如:
std::ostream& operator<<(std::ostream& out, const AutoData& dasAuto) {
return out << dasAuto.getmpg() << ':' << dasAuto.getcylinders() <<
/* insert everthing in the desired order here */
std::endl;
}
“阅读”功能也是如此,例如:
std::istream& operator>>(std::istream& in, AutoData& dasAuto) {
float mpg;
int cylinders;
float displacement;
float horsepower;
float weight;
float acceleration;
int modelYear;
int origin;
string carName;
char separator;
const char SEP = ':';
if( !(in >> mpg >> separator) || (separator != SEP) ) return in;
if( !(in >> cylinders >> separator) || (separator != SEP) ) return in;
/* rinse, repeat */
if( !std::getline(in, carName) ) return in;
dasAuto.setAuto(mpg, cylinders /*, etc etc */);
return in;
}
你可以阅读这篇文章来了解friend
和operator <<
, http: //www.cprogramming.com/tutorial/friends.html
在AutoData
类中,你应该声明这个函数:
friend ostream& operator<< (ostream& out, const AutoData& obj);
在类之外,你应该像这样定义这个函数:
ostream& operator<< (ostream& out, const AutoData& obj)
{
out<<obj.mpg<<":";
//do what you want
return out;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.