检测鼠标方向 - JavaScript

Question

var direction = ""
var mousemovemethod = function (e) {
    var oldx = 0;
    if (e.movementX < oldx) {
        direction = "left"
    } else if (e.movementX > oldx) {
        direction = "right"
    }
    oldx = e.pageX;
}

这就是我检测鼠标方向的方式，它非常有效，但仅适用于 Chrome，我如何使其与其他浏览器（Firefox、Opera 和至少 ie8+ 或 ie9+）兼容。 请不要使用jQuery。

Answer 1

坚持使用pageX并在更高的范围内定义oldx ，否则它始终为零

var direction = "",
    oldx = 0,
    mousemovemethod = function (e) {

        if (e.pageX < oldx) {
            direction = "left"
        } else if (e.pageX > oldx) {
            direction = "right"
        }

        oldx = e.pageX;

}

小提琴

Answer 2

鼠标移动 - 向左、向右、向上、向下 - javascript FIDDLE

 var direction = ""; var oldx = 0; var oldy = 0; mousemovemethod = function (e) { if (e.pageX > oldx && e.pageY == oldy) { direction="East"; } else if (e.pageX == oldx && e.pageY > oldy) { direction="South"; } else if (e.pageX == oldx && e.pageY < oldy) { direction="North"; } else if (e.pageX < oldx && e.pageY == oldy) { direction="West"; } document.body.innerHTML = direction; oldx = e.pageX; oldy = e.pageY; } document.addEventListener('mousemove', mousemovemethod);

Answer 3

此代码将为您提供方向 X 和方向 Y 变量中“X”和“Y”的“方向”以及“X”和“Y”轴行进的距离。

 let oldX = 0, oldY = 0;

 function captureMouseMove($event){
      let directionX = 0, directionY = 0, diffX = 0, diffY = 0;
      if ($event.pageX < oldX) {
          directionX = "left"
          diffX = oldX - $event.pageX;
      } else if ($event.pageX > oldX) {
          directionX = "right"
          diffX = $event.pageX - oldX;
      }

      if ($event.pageY < oldY) {
          directionY = "top"
          diffY = oldY - $event.pageY;
      } else if ($event.pageY > oldY) {
          directionY = "bottom";
          diffY = $event.pageY - oldY;
      }

      oldX = $event.pageX;
      oldY = $event.pageY;
  }

  window.addEventListener('mousemove', captureMouseMove);

Answer 4

您不需要跟踪旧位置。

   e.clientX - window.innerWidth/2 > 0 ? 'right' : 'left'
   e.clientY - window.innerHeight/2 > 0 ? 'bottom' : 'top'

Answer 5

let direction = "";
if (e.movementY > 0 && e.movementX == 0) {
    direction = "down";
  } else if (e.movementY < 0 && e.movementX == 0) {
    direction = "up";
  } else if (e.movementX > 0 && e.movementY == 0) {
    direction = "right";
  } else if (e.movementX < 0 && e.movementY == 0) {
    direction = "left";
  }