依赖注入和传递参数

Question

我有一个关于PHP中的依赖注入的问题。

我目前有这3个课程：

Staff.php

<?php
class Staff
{
    public function name($id)
    {
        return 'returning staff with id ' . $id;
    }
}

Projects.php

<?php
class Projects
{
..... projects related functions
}

ProjectsManager.php

<?php

class ProjectsManager
{
    private $staff = null;
    private $projects = null;

    public function __construct(Staff $staff, Projects $projects)
    {
        $this->staff = $staff;
        $this->projects = $projects;
    }

    public function staff()
    {
        return $this->staff;
    }

    public function projects()
    {
        return $this->projects;
    }
}

这些类的实例化如下：

    $staff    = new Staff;
    $projects = new Projects;
    $app      = new ProjectsManager($staff, $projects);

    echo $app->staff()->name(5);

上面的工作正常，但是我想做的是这样的：

$employee = $app->staff(5);
echo $employee->name();
echo $employee->position();
echo $employee->email();

如何处理依赖关系以实现此目的？

Answer 1

$employee = $app->staff()->name(5);
//$app is the ProjectsManager
//$app->staff() returns it's Staff object
//staff()->name(5) Invokes the Staff object's name function
//Returns 'Returning staff with id 5'    

echo $employee->name();
echo $employee->position();
echo $employee->email();

为了避免混淆，我还建议在其中一些函数的$app->getStaff()->getFromId(#)加上get （例如$app->getStaff()->getFromId(#) ）

另外，请确保修改staff()->name(#)以实际返回对象而不是字符串。

Answer 2

您只需在Staff类中添加set函数，然后在ProjectsManager中调用它即可：

<?php

class Staff 
{
    private $id = null;

    public function name()
    {
        return 'returning staff with id ' . $this->id;
    }

    public function setId($id)
    {
        $this->id = $id;
    }
}


class Projects
{
//..... projects related functions
}

class ProjectsManager
{
    private $staff = null;
    private $projects = null;

    public function __construct(Staff $staff, Projects $projects)
    {
        $this->staff = $staff;
        $this->projects = $projects;
    }

    public function staff($id = null)
    {
        $this->staff->setId($id);
        return $this->staff;
    }

    public function projects($val = null)
    {
        return $this->projects;
    }
}


$staff    = new Staff;
$projects = new Projects;
$app      = new ProjectsManager($staff, $projects);

$employee = $app->staff(5);
echo $employee->name();