在MySQLi上使用'if'[关闭]

Question

编辑：我忘了使用==。 该主题可以关闭。 我希望根据数据库表中的行在下拉列表中选择其他区域。 我以为这段代码可以解决问题，但是它始终选择“是”。 这是我的PHP：

<?php
$con=mysqli_connect("localhost","*******","*********","FRTM");
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$member_number = mysqli_real_escape_string($con, $_POST['last_name']);

echo "<form action='query2.php' method='post'>";

$resultoverall1 = mysqli_query($con,"SELECT * FROM history_overall WHERE member_number='$member_number'");

while($rowo_1 = mysqli_fetch_array($resultoverall1)) {
    if ($rowo_1['board']="Y") {
        echo "<p>Board: <select name='board'>";
        echo "<option value=''>Please Select</option>";
        echo "<option value='Y' selected>Yes</option>";
        echo "<option value='N'>No</option>";
        echo "<option value='NM'>Need Mailing</option>";
        echo "</select></p>";
    }
    elseif ($rowo_1['board']="NM") {
        echo "<p>Board: <select name='board'>";
        echo "<option value=''>Please Select</option>";
        echo "<option value='Y'>Yes</option>";
        echo "<option value='N'>No</option>";
        echo "<option value='NM' selected>Need Mailing</option>";
        echo "</select></p>";
    }
    elseif ($rowo_1['board']="N") {
        echo "<p>Board: <select name='board'>";
        echo "<option value=''>Please Select</option>";
        echo "<option value='Y'>Yes</option>";
        echo "<option value='N' selected>No</option>";
        echo "<option value='NM'>Need Mailing</option>";
        echo "</select></p>";
    }
    }
mysqli_close($con);
?> 

任何帮助表示赞赏。

Answer 1

您只是在if语句中缺少一个=号。 :)

==对吗？

if ($rowo_1['board'] == "Y")