从数组元素中删除/过滤字符和/或单词

Question

我正在尝试从数组的“位置”部分中删除/过滤流浪字符/单词。 到目前为止，不管我做什么，这样做都会输出不需要的字符。

我要摆脱的字符：pic \\ u00a0map

码：

$city = 'Kanosh';
$s = "SELECT * FROM `list` WHERE `city` LIKE '%".$city."%'";
$res = $mysqli->query($s) or trigger_error($mysqli->error."[$s]");
$a = array(); 
while($row = $res->fetch_array(MYSQLI_BOTH)) { 
$a[] = array(
'title' => $row['title'],
'price' => $row['price'],
'rooms' => $row['rooms'],
'dimensions' => $row['dimensions'],
'location' => preg_replace('pic\u00a0map', '', $row['location']),
'price' => $row['price'],
'address' => $row['address'],
'seller' => $row['seller'],
'href' => $row['href'],
'date' => $row['date']
); 
}
header('Content-Type: application/json');
echo json_encode($a);
$res->free();
$mysqli->close();

输出：

[{"title":"Mobile Home Double     Wide","price":"$85000","rooms":"3br","dimensions":"","location":"Kanosh UT     pic\u00a0map","address":"","seller":"real estate - by owner","href":"http:\/\/saltlakecity.craigslist.org","date":"20140811214226"},   {"title":"Mobile Home Double    Wide","price":"$85000","rooms":"3br","dimensions":"","location":"Kanosh UT      pic\u00a0map","address":"","seller":"real estate - by     owner","href":"http:\/\/saltlakecity.craigslist.org","date":"20140811223113"}]

请告知如何删除/过滤/替换数组元素内的字符和/或单词。

Answer 1

在此线程中找到了答案：

回答

对于阅读此书的任何人，请不要忘记解码unicode字符。 它把我甩了。