如何在SQL Server中将参数传递给IN

Question

这是我叫员工的表

-----------------------
Column Name | Data Type
----------------------
ID          | int
EmpId       | nvarchar
Name        | nvarchar
Salary      | decimal

看一下表的所有记录

------------------------------
ID | EmpId |  Name   |  Salary
------------------------------
1  | 200   |  Bulbul | 2000.00
2  | 201   |  Ahmed  | 2000.00
3  | 202   |  Rakib  | 2500.00
4  | 203   |  Rubel  | 3000.00
5  | 204   |  Zia    | 4000.00

现在，如果我想将给定雇员ID的所有记录发送给IN运算符，则会得到以下结果。 很好

SELECT EmpId, Name, Salary
FROM Employee
WHERE EmpId IN ('200','201')

------------------------------
ID | EmpId |  Name   |  Salary
------------------------------
1  | 200   |  Bulbul | 2000.00
2  | 201   |  Ahmed  | 2000.00

但是，如果我将雇员ID作为参数传递，那么我将无法获得理想的结果。 只是得到空的结果。

DECLARE @Params AS NVARCHAR(MAX) = '''200'',''201'''

SELECT EmpId, Name, Salary
FROM Employee
WHERE EmpId IN (@Params)  

------------------------------
ID | EmpId |  Name   |  Salary
------------------------------
   |       |         |  
   |       |         |  

现在，我需要使用IN运算符中的参数来获得以下结果。 我想要的结果是这样的：

------------------------------
ID | EmpId |  Name   |  Salary
------------------------------
1  | 200   |  Bulbul | 2000.00
2  | 201   |  Ahmed  | 2000.00

请帮助我获得我想要的结果。 预先感谢。

Answer 1

我建议使用表类型参数。

CREATE TYPE dbo.IdList AS TABLE (Id INT)
GO

DECLARE @Ids dbo.IdList 

INSERT INTO @Ids(Id)VALUES(200),(201)

SELECT EmpId, Name, Salary
FROM Employee
WHERE EmpId IN (SELECT Id FROM @Ids)

Answer 2

在下面的表值SQL函数fn_split中添加：

CREATE FUNCTION [dbo].[fn_Split](@sText varchar(8000), @sDelim varchar(20) = ' ')
RETURNS @retArray TABLE (idx smallint Primary Key, value varchar(8000))
AS
BEGIN
DECLARE @idx smallint,
    @value varchar(8000),
    @bcontinue bit,
    @iStrike smallint,
    @iDelimlength tinyint

IF @sDelim = 'Space'
    BEGIN
    SET @sDelim = ' '
    END

SET @idx = 0
SET @sText = LTrim(RTrim(@sText))
SET @iDelimlength = DATALENGTH(@sDelim)
SET @bcontinue = 1

IF NOT ((@iDelimlength = 0) or (@sDelim = 'Empty'))
    BEGIN
    WHILE @bcontinue = 1
        BEGIN

--If you can find the delimiter in the text, retrieve the first element and
--insert it with its index into the return table.

        IF CHARINDEX(@sDelim, @sText)>0
            BEGIN
            SET @value = SUBSTRING(@sText,1, CHARINDEX(@sDelim,@sText)-1)
                BEGIN
                INSERT @retArray (idx, value)
                VALUES (@idx, @value)
                END

--Trim the element and its delimiter from the front of the string.
            --Increment the index and loop.
SET @iStrike = DATALENGTH(@value) + @iDelimlength
            SET @idx = @idx + 1
            SET @sText = LTrim(Right(@sText,DATALENGTH(@sText) - @iStrike))

            END
        ELSE
            BEGIN
--If you can’t find the delimiter in the text, @sText is the last value in
--@retArray.
 SET @value = @sText
                BEGIN
                INSERT @retArray (idx, value)
                VALUES (@idx, @value)
                END
            --Exit the WHILE loop.
SET @bcontinue = 0
            END
        END
    END
ELSE
    BEGIN
    WHILE @bcontinue=1
        BEGIN
        --If the delimiter is an empty string, check for remaining text
        --instead of a delimiter. Insert the first character into the
        --retArray table. Trim the character from the front of the string.
--Increment the index and loop.
        IF DATALENGTH(@sText)>1
            BEGIN
            SET @value = SUBSTRING(@sText,1,1)
                BEGIN
                INSERT @retArray (idx, value)
                VALUES (@idx, @value)
                END
            SET @idx = @idx+1
            SET @sText = SUBSTRING(@sText,2,DATALENGTH(@sText)-1)

            END
        ELSE
            BEGIN
            --One character remains.
            --Insert the character, and exit the WHILE loop.
            INSERT @retArray (idx, value)
            VALUES (@idx, @sText)
            SET @bcontinue = 0  
            END
    END

END

RETURN
END

并执行以下查询以获取输出：

DECLARE @Params AS NVARCHAR(MAX) = '200,201'
SELECT EmployeeId, Name
FROM Employee
WHERE EmployeeId IN (select value from dbo.fn_Split(@Params,','))

希望这可以帮助！

Answer 3

请试试：

DECLARE @Params AS NVARCHAR(MAX) = '200,201'

exec ('SELECT EmpId, Name, Salary
       FROM Employee
       WHERE EmpId IN ('+@Params+')')

Answer 4

最后，我得到了预期的结果，例如：

CREATE TABLE #EmpTable
(
  EmpId NVARCHAR (50) NULL
)
GO
DECLARE @Parameter AS NVARCHAR(MAX) = '(''201''),(''202'')'
DECLARE @SQL AS NVARCHAR(MAX) ='INSERT INTO #EmpTable (EmpId)VALUES' + @Parameter
EXEC (@SQL)
GO
SELECT EmpId, Name, Salary
FROM Employee
WHERE EmpId IN (SELECT EmpId FROM #EmpTable)