Slick.js：获取当前和总幻灯片（即 3/5）

Question

使用Slick.js - 如何获得当前和总幻灯片（即 3/5）作为点的更简单替代方法？

有人告诉我，我可以使用回调参数对象来使用customPaging回调，但这究竟是什么意思？

$('.slideshow').slick({
    slide: 'img',
    autoplay: true,
    dots: true,
    customPaging: function (slider, i) {
        return slider.slickCurrentSlide + '/' + (i + 1);
    }
});

http://jsfiddle.net/frank_o/cpdqhdwy/1/

Answer 1

slider对象包含幻灯片计数作为属性。

光滑 < 1.5

$('.slideshow').slick({
    slide: 'img',
    autoplay: true,
    dots: true,
    dotsClass: 'custom_paging',
    customPaging: function (slider, i) {
        //FYI just have a look at the object to find available information
        //press f12 to access the console in most browsers
        //you could also debug or look in the source
        console.log(slider);
        return  (i + 1) + '/' + slider.slideCount;
    }
});

演示

Slick 1.5+ 的更新（测试到 1.8.1）

var $status = $('.pagingInfo');
var $slickElement = $('.slideshow');

$slickElement.on('init reInit afterChange', function(event, slick, currentSlide, nextSlide){
    //currentSlide is undefined on init -- set it to 0 in this case (currentSlide is 0 based)
    var i = (currentSlide ? currentSlide : 0) + 1;
    $status.text(i + '/' + slick.slideCount);
});

$slickElement.slick({
    slide: 'img',
    autoplay: true,
    dots: true
});

演示

Slick 1.9+ 的更新

var $status = $('.pagingInfo');
var $slickElement = $('.slideshow');

$slickElement.on('init reInit afterChange', function(event, slick, currentSlide, nextSlide){
    //currentSlide is undefined on init -- set it to 0 in this case (currentSlide is 0 based)
    var i = (currentSlide ? currentSlide : 0) + 1;
    $status.text(i + '/' + slick.slideCount);
});

$slickElement.slick({
    autoplay: true,
    dots: true
});

演示

使用slidesToShow时的slidesToShow

var $status = $('.pagingInfo');
var $slickElement = $('.slideshow');

$slickElement.on('init reInit afterChange', function (event, slick, currentSlide, nextSlide) {
  // no dots -> no slides
  if(!slick.$dots){
    return;
  }
  
  //currentSlide is undefined on init -- set it to 0 in this case (currentSlide is 0 based)
  var i = (currentSlide ? currentSlide : 0) + 1;
  // use dots to get some count information
  $status.text(i + '/' + (slick.$dots[0].children.length));
});

$slickElement.slick({
  infinite: false,
  slidesToShow: 4,
  autoplay: true,
  dots: true
});

演示

Answer 2

您需要在初始化之前绑定 init。

$('.slider-for').on('init', function(event, slick){
        $(this).append('<div class="slider-count"><p><span id="current">1</span> von <span id="total">'+slick.slideCount+'</span></p></div>');
    });
    $('.slider-for').slick({
      slidesToShow: 1,
      slidesToScroll: 1,
      arrows: true,
      fade: true
    });
    $('.slider-for')
        .on('afterChange', function(event, slick, currentSlide, nextSlide){
            // finally let's do this after changing slides
            $('.slider-count #current').html(currentSlide+1);
        });

Answer 3

这可能有帮助：

• 您不需要启用点或 customPaging。
• 使用 CSS 定位 .slick-counter。

CSS

.slick-counter{
  position:absolute;
  top:5px;
  left:5px;
  background:yellow;
  padding:5px;
  opacity:0.8;
  border-radius:5px;
}

JavaScript

var $el = $('.slideshow');

$el.slick({
  slide: 'img',
  autoplay: true,
  onInit: function(e){
    $el.append('<div class="slick-counter">'+ parseInt(e.currentSlide + 1, 10) +' / '+ e.slideCount +'</div>');
  },
  onAfterChange: function(e){
    $el.find('.slick-counter').html(e.currentSlide + 1 +' / '+e.slideCount);
  }
});

http://jsfiddle.net/cpdqhdwy/6/

Answer 4

我使用此代码并且它有效：

.slider - 这是滑块

.count - 用于返回计数器的选择器

$(".slider").on("init", function(event, slick){
    $(".count").text(parseInt(slick.currentSlide + 1) + ' / ' + slick.slideCount);
});

$(".slider").on("afterChange", function(event, slick, currentSlide){
    $(".count").text(parseInt(slick.currentSlide + 1) + ' / ' + slick.slideCount);
});
$(".page-article-item_image-slider").slick({
    slidesToShow: 1,
    arrows: true
});

Answer 5

基于@Mx 发布的第一个命题。 （2014 年 9 月 15 日发布）我创建了一个变体来获得一个体面的 HTML 标记来支持ARIA 。

$('.slideshow').slick({
    slide: 'img',
    autoplay: true,
    dots: true,
    dotsClass: 'custom_paging',
    customPaging: function (slider, i) {
        //FYI just have a look at the object to find available information
        //press f12 to access the console in most browsers
        //you could also debug or look in the source
        console.log(slider);
        var slideNumber   = (i + 1),
            totalSlides = slider.slideCount;
        return '<a class="custom-dot" role="button" title="' + slideNumber + ' of ' + totalSlides + '"><span class="string">' + slideNumber + '</span></a>';
    }
});

jsFiddle 演示

Answer 6

使用以前的方法一次超过 1 张幻灯片给了我错误的总数，所以我使用了“dotsClass”，就像这样（在 v1.7.1 上）：

// JS

var slidesPerPage = 6

$(".slick").on("init", function(event, slick){
   maxPages = Math.ceil(slick.slideCount/slidesPerPage);
   $(this).find('.slider-paging-number li').append('/ '+maxPages);
});

$(".slick").slick({
   slidesToShow: slidesPerPage,
   slidesToScroll: slidesPerPage,
   arrows: false,
   autoplay: true,
   dots: true,
   infinite: true,
   dotsClass: 'slider-paging-number'
});

// CSS

ul.slider-paging-number {
    list-style: none;
    li {
        display: none;
        &.slick-active {
            display: inline-block;
        }
        button {
            background: none;
            border: none;
        }
    }
}

Answer 7

Modifications are done to the new Slick version 1.7.1.

这是一个更新的脚本示例： jsfiddle

Answer 8

如果你想要页码：

示例： 1 2 3 4...

HTML：

<div class="slider">
  <div>
    <div>Some content</div>
    <div class="slider-number"><span>1 2 3 4...</span></div>
  </div>
  <div>
    <div>Some content</div>
    <div class="slider-number"><span>1 2 3 4...</span></div>
  </div>
  ...
  ...
</div>

JS：

$('.slider').on('init reInit afterChange',
    function(event, slick, currentSlide){
        var status = $(this).find('.slider-number span');
        //currentSlide is undefined on init -- set it to 0 in this case (currentSlide is 0 based)
        var i = slick.currentSlide;
        var slidesLength = slick.slideCount;
        var numberSlide1 = i + 1 <= slidesLength ? i + 1 : i - (slidesLength - 1);
        var numberSlide2 = i + 2 <= slidesLength ? i + 2 : i - (slidesLength - 2);
        var numberSlide3 = i + 3 <= slidesLength ? i + 3 : i - (slidesLength - 3);
        var numberSlide4 = i + 4 <= slidesLength ? i + 4 : i - (slidesLength - 4);

        status.html('<strong>'+numberSlide1+'</strong>' + ' ' +
            numberSlide2 + ' ' +
            numberSlide3 + ' ' +
            numberSlide4 + '...');
});

JsFiddle 演示

Answer 9

我有多个幻灯片的问题。 版本1.8.1

如果slidesToShow和slidesToScroll超过1

技巧在slick.slickGetOption('slidesToShow');

$(".your-selector").on('init reInit afterChange', function(event, slick, currentSlide, nextSlide){
    var i = (currentSlide ? currentSlide : 0) + 1;
    var slidesToShow = slick.slickGetOption('slidesToShow');
    var curPage = parseInt((i-1)/slidesToShow) + 1;
    var lastPage =  parseInt((slick.slideCount-1)/slidesToShow) + 1;
    $('.your-selector').text(curPage);
    $('.your-selector').text(lastPage);
});

注意curPage和lastPage是分开的。 我不得不给它们涂上不同的颜色。

基于最高投票的答案