根据日期获取用户数

Question

我有一个简单的表，其中存储用户ID，用户名，电子邮件，RegistrationDate ...

RegistrationDate是DateTime数据类型

当我要获取每个日期的用户数时，由于每行都有唯一的dateTime时间戳，因此每行给我1。

SELECT DATEPART(dd, RegistrationDate) AS DD, COUNT(userID)   
FROM USER_Table 
GROUP BY RegistrationDate 
order by RegistrationDate DESC

如果我有100个用户注册，ABove查询会让我每100行。

我想获得基于日期的计数。 我尝试了其他事情，但似乎没有任何效果。

Answer 1

尝试这个 ：

SELECT Cast(RegistrationDate AS DATE),
       Count(userID)
FROM   User_Table
GROUP  BY Cast(RegistrationDate AS DATE)
ORDER  BY Cast(RegistrationDate AS DATE)DESC 

Answer 2

您需要按CAST(RegistrationDate as Date)分组CAST(RegistrationDate as Date)

SELECT CAST(RegistrationDate as Date) AS [Date], COUNT(userID)   
FROM USER_Table 
GROUP BY CAST(RegistrationDate as Date)
order by CAST(RegistrationDate as Date) DESC

Answer 3

SELECT cast(RegistrationDate as Date) AS DD, COUNT(userID)   
FROM USER_Table 
GROUP BY cast(RegistrationDate as Date)
order by cast(RegistrationDate as Date) DESC