汇总函数出错

Question

当我执行以下查询时，出现错误“无法对包含聚合或子查询的表达式执行聚合函数”。 我如何才能在不出错的情况下编写相同的查询。

SELECT CCMID[Client],CCMName[Company],
    (SELECT SUM( (Select SUM( PAm) from PaySalReg(NOLOCK) 
    Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
    where PSRAMId=AMId and PEMDedTy ='SSC' 
    and PProYe=(SELECT DOYe FROM DefOMonth)
    and PProMo=(SELECT DOMo-1 FROM DefOMonth))
    -
    (Select SUM(PAm) from PaySalReg(NOLOCK) 
    Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
    where PSRAMId=AMId and PEMDedTy ='PRTY'
    and PProYe=(SELECT DOYe FROM DefOMonth)
    and PProMo=(SELECT DOMo-1 FROM DefOMonth)))
    from AssMas(NOLOCK) WHERE ACID = CCMID ) AS [Net Pay],
    COUNT(PAMId)[No. of Associates] 
    FROM PaySalReg
    JOIN AssMas ON AMId =PSRAMId
    JOIN CorpClMas ON ACID = CCMID
    WHERE PProMon='10'
    AND PProYe='2014'
    AND PAPPSTA IS NULL
    GROUP BY CCM_Name,CCM_ID

Answer 1

您可以删除外部聚合，然后将查询包装在子查询中...然后在子查询上执行聚合...类似这样的事情...

SELECT CCMID, CCMName, [No. of Associates], SUM([Net Pay])
FROM (
    SELECT Client as CCMID, Company as CCMName,
        (Select SUM( PAm) from PaySalReg(NOLOCK) 
        Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
        where PSRAMId=AMId and PEMDedTy ='SSC' 
        and PProYe=(SELECT DOYe FROM DefOMonth)
        and PProMo=(SELECT DOMo-1 FROM DefOMonth))
        -
        (Select SUM(PAm) 
        from PaySalReg(NOLOCK) 
        Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
        where PSRAMId=AMId and PEMDedTy ='PRTY'
        and PProYe=(SELECT DOYe FROM DefOMonth)
        and PProMo=(SELECT DOMo-1 FROM DefOMonth)) AS [Net Pay],

        COUNT(PAMId) AS [No. of Associates] 
    FROM PaySalReg
        JOIN AssMas ON AMId =PSRAMId
        JOIN CorpClMas ON ACID = CCMID
    WHERE PProMon='10'
    AND PProYe='2014'
    AND PAPPSTA IS NULL) data
GROUP BY CCMID, CCMName, [No. of Associates]

（未经测试，因为您没有提供数据结构。）

Answer 2

尝试将聚合查询移至新函数（标量函数）并从过程中调用该函数。（用函数替换聚合查询）

Answer 3

我修复了您的编码样式和缩进，问题变得明显了：

SELECT
    CCMID[Client],
    CCMName[Company],
    (
        SELECT SUM(
            (   
                Select SUM(PAm) from PaySalReg(NOLOCK) 
                Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
                where PSRAMId = AMId
                    and PEMDedTy = 'SSC' 
                    and PProYe = (SELECT DOYe FROM DefOMonth)
                    and PProMo = (SELECT DOMo-1 FROM DefOMonth)
            ) - (
                Select SUM(PAm) from PaySalReg(NOLOCK) 
                Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
                where PSRAMId = AMId
                    and PEMDedTy = 'PRTY'
                    and PProYe = (SELECT DOYe FROM DefOMonth)
                    and PProMo = (SELECT DOMo-1 FROM DefOMonth)
            )
        )
        from AssMas(NOLOCK)
        WHERE ACID = CCMID
    ) AS [Net Pay],

    COUNT(PAMId) [No. of Associates] 

FROM PaySalReg
JOIN AssMas    ON AMId = PSRAMId
JOIN CorpClMas ON ACID = CCMID
WHERE  PProMon = '10'
    AND PProYe = '2014'
    AND PAPPSTA IS NULL
GROUP BY CCM_Name, CCM_ID

第4行中的SUM()是问题所在。 而且我根本不知道为什么将SUM()放在那儿，因为没有GROUP BY ，所以要减去的2个子查询每个都只会给出1个结果。 因此， value - value周围不需要SUM() ：

SELECT
    CCMID[Client],
    CCMName[Company],
    (
        SELECT (    
                Select SUM(PAm) from PaySalReg(NOLOCK) 
                Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
                where PSRAMId = AMId
                    and PEMDedTy = 'SSC' 
                    and PProYe = (SELECT DOYe FROM DefOMonth)
                    and PProMo = (SELECT DOMo-1 FROM DefOMonth)
            ) - (
                Select SUM(PAm) from PaySalReg(NOLOCK) 
                Join PayEleMas (NOLOCK) ON  PSPCo =PEPCo
                where PSRAMId = AMId
                    and PEMDedTy = 'PRTY'
                    and PProYe = (SELECT DOYe FROM DefOMonth)
                    and PProMo = (SELECT DOMo-1 FROM DefOMonth)
            )
        from AssMas(NOLOCK)
        WHERE ACID = CCMID
    ) AS [Net Pay],

    COUNT(PAMId) [No. of Associates] 

FROM PaySalReg
JOIN AssMas    ON AMId = PSRAMId
JOIN CorpClMas ON ACID = CCMID
WHERE  PProMon = '10'
    AND PProYe = '2014'
    AND PAPPSTA IS NULL
GROUP BY CCM_Name, CCM_ID

旁注：此查询肯定看起来可以重构，但这不是您的问题:)