[英]Creating a Deck of Cards using an ArrayList
我知道以前很多人都问过这个问题(在来到这里之前我环顾了一下),但是我似乎无法弄清楚如何解决我的代码。 我的任务是制作一个静态makeDeck方法,该方法返回一个ArrayList,其中包含标准纸牌中的52张纸牌。 我是ArrayList的新手,所以我不确定我是否正确初始化了ArrayList的makeDeck。 这是我到目前为止的内容:
public class Card
{
private String mySuit;
private int myValue;
public Card( String suit, int value )
{
mySuit = suit;
myValue = value;
}
public String name()
{
String[] cardNames =
{
"Deuce", "Three", "Four", "Five",
"Six", "Seven", "Eight", "Nine", "Ten",
"Jack", "Queen", "King", "Ace"
};
return cardNames[ myValue - 2 ] + " of " + mySuit;
}
}
public class MainClass
{
public static void displayCards( ArrayList<Card> a )
{
int i;
System.out.println( "Size is " + a.size() );
for ( i = 0 ; i < a.size() ; i++ )
{
Card c = a.get( i );
System.out.println( "#" + (i+1) + ": " + c.name() );
}
}
public static ArrayList<Card> makeDeck()
{
ArrayList<Card> cards = new ArrayList<Card>();
String[] cardNames =
{
"Deuce", "Three", "Four", "Five",
"Six", "Seven", "Eight", "Nine", "Ten",
"Jack", "Queen", "King", "Ace"
};
String[] suits = { "spades", "hearts", "diamonds", "clubs" };
for (int a=0; a<=cardNames.length(); a++)
{
for (int b=0; b<= suits.length(); b++)
{
cards.add(new Card(cardNames[a], suits[b])); //I've noticed many people use this to add the card names and suits to the cards ArrayList, and it gives me an error of not being able to turn suits[b] into an integer, so I'm confused as to how it worked for others
}
}
return cards;
}
public static void main( String[] args )
{
System.out.println(makeDeck());
}
如果有人可以帮助我弄清楚我在做什么错,我将不胜感激。 谢谢!
您正在将两个String传递给Card
构造函数。 在您编辑Card
类的代码之前,我看到您的构造函数需要一个String和一个int。 这就是构造函数调用无法编译的原因。
另外,您忘了在makeDeck()
方法中返回值,并且您的cards
列表在该方法的本地,因此您无法从主方法访问它,而且您也没有cards()
方法。
您的主要方法应为:
public static void main( String[] args )
{
System.out.println(makeDeck());
}
您的makeDeck()
应该有一个return cards;
最后一行中的语句。
您应该更改Card
类的构造函数或更改传递给它的argumnet。
使用Card类的当前实现,您可能应该将Card创建循环更改为:
for (int a=0; a < suits.length; a++)
{
for (int b=0; b< 13 ; b++)
{
cards.add(new Card(suits[a],b));
}
}
不过,您可能必须更改Card
的name()
方法。
您需要使makeDeck()
返回cards
。 同样在您的主打印语句中,您遇到要调用makeDeck()
而不是cards()
关于您的错误string cannot be converted to int
您需要执行以下两项操作之一:
1)更改Card类构造函数以采用两个字符串:
Public Card(string value, string suit)
并将int myValue
更改为string myValue
2)将您的cardName数组更改为int
而不是string
。 您也可以全部忽略cardNames
,然后将其更改为以下内容:
cards.add(new Card(suits[b], a+1));
添加return
语句,该语句将返回您的数组列表。
public static ArrayList<Card> makeDeck()
{
ArrayList<Card> cards = new ArrayList<Card>();
String[] cardNames =
{
"Deuce", "Three", "Four", "Five",
"Six", "Seven", "Eight", "Nine", "Ten",
"Jack", "Queen", "King", "Ace"
};
String[] suits = { "spades", "hearts", "diamonds", "clubs" };
for (int a=0; a<=12; a++)
{
for (int b=0; b<=3; b++)
{
cards.add(new Card(cardNames[a], suits[b])); //I've noticed many people use this to add the card names and suits to the cards ArrayList, and it gives me an error of not being able to turn suits[b] into an integer, so I'm confused as to how it worked for others
}
}
return cards;
}
从您的主要方法调用makeDeck()
。
public static void main( String[] args ){
ArrayList<Card> cards = makeDeck();
for(Card c : cards){
System.out.println("You can print card member variables here");
}
}
看来您忘了在方法结束时return
,
public static ArrayList<Card> makeDeck()
{
ArrayList<Card> cards = new ArrayList<Card>();
String[] cardNames =
{
"Deuce", "Three", "Four", "Five",
"Six", "Seven", "Eight", "Nine", "Ten",
"Jack", "Queen", "King", "Ace"
};
String[] suits = { "spades", "hearts", "diamonds", "clubs" };
for (int a=0; a<=12; a++)
{
for (int b=0; b<=3; b++)
{
cards.add(new Card(cardNames[a], b)); // <-- if the second Card
// parameter whould be an int.
}
}
return cards;
}
而且您应该调用makeDeck()
而不是cards()
System.out.println(makeDeck());
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.