Pandas DataFrame：从列内的列表创建列

Question

我正在使用熊猫DataFrame'test_df'：

email                      my_list
email1@email1.com          [1,9,3,5]
email2@email2.com          [6,3,3,15]
email3@email3.com          [7,7,2,5]
email4@email4.com          [5,5,5,5]

我如何在DataFrame之后获得此数据（取“ my_list”的前2个元素）：

email                      col1             col2             
email1@email1.com          1                9        
email2@email2.com          6                3
email3@email3.com          7                7
email4@email4.com          5                5           

我试过了：

test_df['col1'] = test_df['my_list'][0]
test_df['col2'] = test_df['my_list'][1]

但这没用

Answer 1

我在这里提出了一个相关的问题，尽管我想将列表扩展成几列，所以答案比您需要的要复杂得多。 就您而言，您可以执行以下操作：

# Using my own example data since it's a bit tough to copy-paste
# a printed table and have the lists show up as lists
df = pd.DataFrame({'email': ['email1@eg.com', 'email2@eg.com'], 
                   'lists': [[1, 9, 3, 5], [6, 3, 3, 15]]})
df
Out[14]: 
           email          lists
0  email1@eg.com   [1, 9, 3, 5]
1  email2@eg.com  [6, 3, 3, 15]

objs = [df, pd.DataFrame(df['lists'].tolist()).iloc[:, :2]]
pd.concat(objs, axis=1).drop('lists', axis=1)
Out[13]: 
           email  0  1
0  email1@eg.com  1  9
1  email2@eg.com  6  3