从表A中选择*，但在第1列中显示它与表B中的匹配项

Question

为措辞严厉的标题道歉，但这是一个例子：

表A.

╔═══╦════════════╦═════════════╗
║   ║ title      ║ creator     ║
╠═══╬════════════╬═════════════╣
║ 1 ║ Lorem      ║ 1           ║
║ 2 ║ Ipsum      ║ 2           ║
║ 3 ║ Dolor      ║ 3           ║
╚═══╩════════════╩═════════════╝

表B.

╔═══╦════════════╦═════════════╗
║   ║ id         ║ name        ║
╠═══╬════════════╬═════════════╣
║ 1 ║ 1          ║ Tom         ║
║ 2 ║ 2          ║ John        ║
║ 3 ║ 3          ║ Harry       ║
╚═══╩════════════╩═════════════╝

是否可以有一个查询将从表A中选择所有，但在结果中它将tableA.creator链接到tableB.name并在结果中显示tableB.name而不是tableA.creator？

Answer 1

SELECT b.name FROM A a LEFT JOIN B b ON a.creator=b.id

Answer 2

SELECT A.Title, B.Name
FROM  TableA as A
INNER JOIN TableB AS B on(A.Creator = B.Id)

Answer 3

SELECT a.title, b.name FROM A a LEFT JOIN B b ON a.creator=b.id

要么

SELECT a.title, b.name
FROM  A as a
JOIN B AS b on a.creator = b.id

Answer 4

尝试以下查询

select distinct A.title , B.name
from A join B
on A.creator = B.id