UIButton调用其选择器操作时获取EXC_BAD_ACCESS

Question

我有这段代码，我试图向视图中的UIButton分配一个操作，最终目的是使它执行传递的闭包。 但是，当我点击该按钮并尝试调用分配给它的操作时，该应用程序会崩溃。

特别是，它显示class AppDelegate: UIResponder, UIApplicationDelegate行，错误为Thread 1: EXC_BAD_ACCESS (code=EXC_I386_GPFLT) 。 我猜想这是Swift所说的safety ...可能是在显式展开的可选对象上做错了什么？

有任何想法吗？

import Foundation
import UIKit

class GenericCustomPopupViewController: UIViewController {
    @IBOutlet weak var containerView: UIView!
    @IBOutlet weak var popupTitleLabel: UILabel!
    @IBOutlet weak var popupBodyLabel: UILabel!
    @IBOutlet weak var okayButton: UIButton!

   // var okayButtonAction: (()->Void)!

    override func viewDidLoad() {

        okayButton.layer.cornerRadius = 17
        okayButton.layer.borderWidth = 1
        okayButton.layer.borderColor = UIColor(red: 195/255, green: 33/255, blue: 121/255, alpha: 1).CGColor

    }

    func showPopupInView(rootView:UIView) {

       // self.okayButtonAction = completion
        self.view.frame = rootView.bounds
        rootView.addSubview(self.view)

        self.okayButton.addTarget(self, action:"buttonTapped:", forControlEvents:.TouchUpInside)

        self.containerView.center.y = -400
        self.containerView.alpha = 0

        UIView.animateWithDuration(0.5, delay: 0.0, usingSpringWithDamping: 0.8, initialSpringVelocity: 2, options: UIViewAnimationOptions.CurveEaseInOut, animations: ({
        self.containerView.center.y = rootView.center.y
        self.containerView.alpha = 1
    }), completion: nil)

}

    func hidePopupView() {
        self.view.removeFromSuperview()
    }

    func buttonTapped(sender: UIButton!) {
       println("test")
    }


}

此UIViewController在父视图中像这样实例化：

var permissionsPopup = GenericCustomPopupViewController(nibName:"LocationPermissionsInfoView", bundle: nil)
    permissionsPopup.showPopupInView(self.view)

Answer 1

啊，找到了。

在.showPopupInView()之后，已释放对GenericCustomPopupViewController的PermissionsPopup引用。 我通过强烈引用它并在以后不再需要它时进行分配来解决了它。