Assembly.Load 3个dll

Question

我有3个dll加载到资源。 它们被切换为嵌入式资源。 我有这样的代码，仅将一个dll加载到Assembly中。 如何加载所有dll？

public partial class Main : Form
{
    public Main()
    {
        AppDomain.CurrentDomain.AssemblyResolve += AssemblyResolve;
        InitializeComponent();

    }

    public static Assembly AssemblyResolve(object sender, ResolveEventArgs args)
    {
        Assembly assembly = Assembly.GetExecutingAssembly();
        using (Stream stream = assembly.GetManifestResourceStream(assembly.GetManifestResourceNames()[3]))
        {
            if (stream == null)
                return null;

            byte[] rawAssembly = new byte[stream.Length];
            stream.Read(rawAssembly, 0, (int)stream.Length);  
            return Assembly.Load(rawAssembly);
        }
    }

Answer 1

您正在调用索引3（奇怪的是，它不会失败，因为您有3个dll，它们应该放在[0] [1] [2]。也许是因为您有与dll分开的资源？无论如何，您都可以做一个简单循环。

    for (int i = 1; i <= 3; i++) // Your dll's seem to be stored from index 1
    using (Stream stream = assembly.GetManifestResourceStream(assembly.GetManifestResourceNames()[i]))
        {
            if (stream == null)
                return null;

            byte[] rawAssembly = new byte[stream.Length];
            stream.Read(rawAssembly, 0, (int)stream.Length);  
            return Assembly.Load(rawAssembly);
        }

那应该做