如何在Java中使用params泛化可调用对象？

Question

我有这两种方法

private void saveBaseLineLatency(E2EResultShort e2EResultShort) {
    LatencyHistogram latencyHistogram = getLatencyHistogram(e2EResultShort);
    latencyDrillDownRepository.saveBaseLine(latencyHistogram);
    saveLatencyTable(latencyHistogram);
}

private void saveFreshTestLatency(E2EResultShort e2EResultShort) {
    System.out.println("log: before saveLatencyHistogram");
    LatencyHistogram latencyHistogram = getLatencyHistogram(e2EResultShort);
    latencyDrillDownRepository.save(latencyHistogram);
    saveLatencyTable(latencyHistogram);
}

如何重构他们的通用代码？

我以为可以使用Callable，但其call()是无参数的。

Answer 1

Consumer是您想要的界面。 它是Java 8中新的java.util.function包的一部分，因此，如果您使用的是Java的旧版本，则此功能将无效。 （该软件包还具有许多类似的其他接口，例如带有两个参数的BiConsumer以及用于使用各种基本类型的接口。）

因此，您的辅助方法将类似于：

private void doLatencyOperation (E2EResultShort newThing, Consumer<LatencyHistogram> consumer) {
  LatencyHistogram lh = getLatencyHistogram(newThing);
  consumer.accept(lh);
  saveLatencyTable(lh);
}

你可以这样称呼它

private void saveBaseLineLatency(E2EResultShort e2EResultShort) {
  doLatencyOperation(e2EResultShort, (lh) -> latencyDrillDownRepository.saveBaseLine(lh));
}

Answer 2

创建一个抽象类，然后将所有通用代码移到那里。

public abstract class MyClass{

public MyClass(E2EResultShort result, latencyDrillDownRepository){
    this.result = result;
}

public void execute() {

 LatencyHistogram latencyHistogram = getLatencyHistogram(e2EResultShort);
callMe(latencyHistogram, latencyDrillDownRepository);
saveLatencyTable(latencyHistogram);

}

public abstract void callMe(LatencyHistogram latencyHistogram, latencyDrillDownRepository); }`

现在，在您的方法中，创建具体的MyClass：

private void saveFreshTestLatency(E2EResultShort e2EResultShort) {

System.out.println("log: before saveLatencyHistogram");
MyClass myClass = new MyClass(e2EResultShort, latencyDrillDownRepository){
    public void callMe(LatencyHistogram latencyHistogram, latencyDrillDownRepository){
        latencyDrillDownRepository.save(latencyHistogram);
    }
}

myClass.execute();

}