＃1111-无效使用组功能

Question

以下查询失败并抱怨#1111 - Invalid use of group function由于IF循环中嵌入了两个SUM（）调用#1111 - Invalid use of group function 。 到现在为止，我试图在迁移到另一个SQL查询时实现相同的目标，但是我遇到了麻烦，请问有人可以向我指出正确的方向吗？

数据库由invoices表组成，如果客户没有一次支付发票而转为分期付款，则invoices表可能会有一些invoices_payments 。 众所周知，我试图将所有invoices.invoice_total减去所有invoices_payments.payment_date，这不等于当前周，仅当invoices.issued_date等于当前周时，否则，我试图对所有invoices_payments.payment_amount求和.payment_date等于当前星期。

SELECT
    SUM(

        IF (
            YEARWEEK(i.issue_date, 1) = YEARWEEK(NOW(), 1),
            i.invoice_total,
            0
        )
    ) AS week_invoiced,
    ##SUM Functions embedded inside the next IF are causing error: #1111 - Invalid use of group function
    SUM(

        IF (
            ## If payment is issued on current week
            i.issued_date IS NOT NULL
            AND YEARWEEK(i.issued_date, '%Y%m') = YEARWEEK(NOW(), '%Y%m'),
            ## Sum each invoice.invoice_total and substract each invoices_payments not issued on current week
            SUM(i.invoice_total) - SUM(

                IF (
                    ip.id IS NOT NULL
                    AND YEARWEEK(ip.payment_date, 1) != YEARWEEK(NOW(), 1),
                    ip.payment_amount,
                    0
                )
            ),

        IF (
            ## If payment is not issued on current week
            i.issued_date IS NULL
            OR (
                i.issued_date IS NOT NULL
                AND YEARWEEK(i.issued_date, '%Y%m') != YEARWEEK(NOW(), '%Y%m')
            ),
            ## Sum each invoices_payments issued on current week
            SUM(

                IF (
                    ip.id IS NOT NULL
                    AND YEARWEEK(ip.payment_date, 1) = YEARWEEK(NOW(), 1),
                    ip.payment_amount,
                    0
                )
            ),
            0
        )
        )
    ) AS week_paid,
    SUM(

        IF (
            DATE_FORMAT(i.issue_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m'),
            i.invoice_total,
            0
        )
    ) AS month_invoiced
FROM
    `invoices` AS i
INNER JOIN `currency` AS cur ON i.currency_id = cur.id
LEFT JOIN `invoices_payments` AS ip ON ip.invoice_id = i.id
WHERE
    i.coach_id = 279
AND (
    DATE_FORMAT(i.issue_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
    OR DATE_FORMAT(i.issued_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
    OR (
        ip.id IS NOT NULL
        AND DATE_FORMAT(ip.payment_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
    )
)
GROUP BY
    i.id

Answer 1

您不需要问题所在的外部SUM 。 也就是说，内部的SUM满足：

SUM( SUM()-SUM() )

->

SUM()-SUM()